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2013-02-23T02:42:45.130
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<p>The <code>run</code> method that is implemented by a thread needs to be in a separate class. You can certainly put one of them in your <code>ThreadExperiment</code> class, but it can't be both. In this case, you can separate the two threads into inner classes:</p> <pre><code>class ThreadExperiment { static int num = 1; static int num2 = 10; class Thread1 implements Runnable { @Override public void run(){ do { num++; try { Thread.sleep(400); } catch (InterruptedException e){ } } while (num >= 0); } } class Thread2 implements Runnable { @Override public void run() { do { num2--; try { Thread.sleep(400); } catch (InterruptedException e){ } } while (num >= 1); } } public static void main(String[] args) { Thread t = new Thread(new Thread1()); Thread t2 = new Thread(new Thread2()); t.start(); t2.start(); if (num == num2) { t.interrupt(); t2.interrupt(); } } } </code></pre> <p>Now we're getting somewhere, but you still need to fix some issues with your logic:</p> <ul> <li>Having the <code>int</code>s as static isn't good practice. (But it's okay for this testing scenario.)</li> <li>Your <code>num == num2</code> check will happen only once and there are no guarantees on what the values will be there when that happens. It is very unlikely that the threads will be interrupted.</li> <li>You need to declare the <code>int</code>s <code>volatile</code> since they will be read by different threads.</li> <li>The <code>while</code> condition in <code>Thread1</code> will result in an infinite loop.</li> </ul>
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1. POThreads and public void run()
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1. USAndrew Mao
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1. COThank you for helping me with the logic - I understand more what logic actually is. And I see how I can add new threads to one class, this really helps, thank you.
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  USTom Pengelly

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