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  1. POHow can I display pictures from the database into heredoc?
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    <p>I have been trying to display Images into the heredoc it can’t work and I get no errors But if I display them out if the heredoc they displayed nicely . what might be the problem? For any help I will appreciate it . Here is the code and I did display the Images twice , in heredoc and out so that u get a clear view .</p> <pre><code>&lt;?Php $target = "image_uploads/"; $image_name = (isset($_POST['image_name'])); $query ="select * from tish_user inner join tish_images on tish_user.user_id = tish_images.user_id WHERE tish_images.prof_image = 1"; $result= $con-&gt;prepare($query); $result-&gt;execute(); $table = &lt;&lt;&lt;ENDHTML &lt;div style ="text-align:center;"&gt; &lt;h2&gt;Client Review Software&lt;/h2&gt; &lt;table id ="heredoc" border ="0" cellpaddinig="2" cellspacing="2" style = "width:100%" ; margin-left:auto; margin-right: auto;&gt; &lt;tr&gt; &lt;th&gt;Name&lt;/th&gt; &lt;th&gt;Last Name&lt;/th&gt; &lt;th&gt;Ref No&lt;/th&gt; &lt;th&gt;Cell&lt;/th&gt; &lt;th&gt;Picture&lt;/th&gt; &lt;/tr&gt; ENDHTML; while($row = $result-&gt;fetch(PDO::FETCH_ASSOC)){ $date_created = $row['date_created']; $user_id = $row['user_id']; $username = $row['username']; $image_id = $row['image_id']; #this is the Tannery operator to replace a pic when an id do not have one $photo = ($row['image_name']== null)? "me.png":$row['image_name']; #display image # I removed this line up to here echo '&lt;img src="'.$target.$photo.'" width="100" height="100"&gt;'; $table .= &lt;&lt;&lt;ENDINFO &lt;tr&gt; &lt;td&gt;&lt;a href ="client_details.php?user_id=$user_id"&gt;$username &lt;/a&gt;&lt;/td&gt; &lt;td&gt;$image_id&lt;/td&gt; &lt;td&gt;&lt;/td&gt; &lt;td&gt;c&lt;/td&gt; &lt;td&gt;&lt;img src="'.$target.$photo.'" width="100" height="100"&gt; &lt;/td&gt; &lt;/tr&gt; ENDINFO; } $table .= &lt;&lt;&lt;ENDHTML &lt;/table&gt; &lt;p&gt;$numrows"Clients&lt;/p&gt; &lt;/div&gt; ENDHTML; echo $table; ?&gt; </code></pre>
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