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POgetting the edge value of a 2D array while preventing getting out of bounds
 

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  1. POgetting the edge value of a 2D array while preventing getting out of bounds
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    <p>I have 4x4 character array here and I need to get the common value of the character that is on the edge of the array...I tried the solutions from other questions similar to my problem, but I am still getting the same error., </p> <p>here's my code..</p> <pre><code>//arr2[][] // arr2[3][0] = 'H'; // arr2[3][1] = 'E'; // arr2[3][2] = 'L'; // arr2[3][3] = 'P'; //arr3[][] // arr3[1][3] = 'T'; // arr3[2][3] = 'O'; // arr3[3][3] = 'P'; //I specifically need the get the 'P' at [3][3].. for(o = 0;o&lt;count;o++){ char letter = out.charAt(o); for(int m = 0; m &lt; 4; m ++){ for(int n = 0; n &lt; 4; n ++){ if(Arrays.asList(arr3[m][n]).contains(letter)){ r = m; c = n; } } } right = arr2[r][c+1]; left = arr2[r][c-1]; up = arr2[r-1][c]; down = arr2[r+1][c]; if(o==0){ if(c==0){ if(r==0||r==3){ if(right!=null){ l = right; } }else{ if(right!=null){ l = right; }else if(up!=null){ l = up; } } }else if(c==3){ if(r==0||r==3){ if(left!=null){ l = left; } }else{ if(left!=null){ l = left; }else if(up!=null){ l = up; } } }else{ if(r==0||r==3){ if(left!=null){ l = left; }else if(right!=null){ l = right; } }else{ if(left!=null){ l = left; }else if(right!=null){ l = right; }else if(up!=null){ l = up; } } } } }else if(o==(count-1)){ if(vertical == 1){ if(c==0){ if(r==0||r==3){ if(right!=null){ l = right; } }else{ if(right!=null){ l = right; }else if(down!=null){ l = down; } } }else if(c==3){ if(r==0||r==3){ if(left!=null){ l = left; } }else{ if(left!=null){ l = left; }else if(down!=null){ l = down; } } }else{ if(r==0||r==3){ if(left!=null){ l = left; }else if(right!=null){ l = right; } }else{ if(left!=null){ l = left; }else if(right!=null){ l = right; }else if(down!=null){ l = down; } } } } }else{ if(vertical == 1){ if(c==0){ if(right!=null){ l = right; } }else if(c==3){ if(left!=null){ l = left; } }else{ if(right!=null){ l = right; }else if(left!=null){ l = left; } } } } k = Character.toString(letter); letr = Character.toString(l); </code></pre>
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    1. USkathy
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    1. COWhy do you write `if(Arrays.asList(arr3[m][n]).contains(letter)){` instead of `if (arr3[m][n] == letter){` ??
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      1. USjlordo
    2. CO@jlordo I have other programs above this one, I created a string from the values of arr3 which is TOP..and I want to know the location of each character and the way to do that is to check if it is contained in arr3[m][n]...
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      1. POgetting the edge value of a 2D array while preventing getting out of bounds
      1. USkathy
    3. COI guess you are getting no anwers, because your code is overly complicated to read. Many `if`, `else if` and `else` cases, with single letter variable names. You say `//I specifically need the get the 'P' at [3][3]..` this can be done by the single line `arr3[3][3]`. I don't understand your code, neither your question. As for my previous comment, both conditions are the same, whereas mine is easy to read and understand (and more efficient), whereas your's is overly complicated.
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      1. POgetting the edge value of a 2D array while preventing getting out of bounds
      1. USjlordo
 

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