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PORegarding finding the middle element of linked list
 

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    <p>I am following the below approach to calculate the middle element from the <code>linked list</code> , but I want is there any built in method or any other approach which can also find the same easily , the approach that I am following is shown bellow..</p> <pre><code>import test.LinkedList.Node; public class LinkedListTest { public static void main(String args[]) { //creating LinkedList with 5 elements including head LinkedList linkedList = new LinkedList(); LinkedList.Node head = linkedList.head(); linkedList.add( new LinkedList.Node("1")); linkedList.add( new LinkedList.Node("2")); linkedList.add( new LinkedList.Node("3")); linkedList.add( new LinkedList.Node("4")); //finding middle element of LinkedList in single pass LinkedList.Node current = head; int length = 0; LinkedList.Node middle = head; while(current.next() != null){ length++; if(length%2 ==0){ middle = middle.next(); } current = current.next(); } if(length%2 == 1){ middle = middle.next(); } System.out.println("length of LinkedList: " + length); System.out.println("middle element of LinkedList : " + middle); } } class LinkedList{ private Node head; private Node tail; public LinkedList(){ this.head = new Node("head"); tail = head; } public Node head(){ return head; } public void add(Node node){ tail.next = node; tail = node; } public static class Node{ private Node next; private String data; public Node(String data){ this.data = data; } public String data() { return data; } public void setData(String data) { this.data = data; } public Node next() { return next; } public void setNext(Node next) { this.next = next; } public String toString(){ return this.data; } } } </code></pre> <h2>Output:-</h2> <pre><code>length of LinkedList: 4 middle element of LinkedList : 2 </code></pre>
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