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  1. PO
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    <p>Try this:</p> <pre><code>SELECT t.ticket_id, ticket_desc, ht.status FROM ticket AS t INNER JOIN history_ticket AS ht ON t.ticket_id = ht.ticket_id INNER JOIN ( SELECT ticket_id, MAX(history_id) maxid FROM history_ticket GROUP BY ticket_id ) AS ht2 ON ht.history_id = ht2.maxid; </code></pre> <h2><a href="http://sqlfiddle.com/#!2/0d086/3" rel="nofollow">SQL Fiddle Demo</a></h2> <p>This will give you:</p> <pre><code>| TICKET_ID | TICKET_DESC | STATUS | ------------------------------------- | 1 | software | process | | 2 | hardware | solve | | 3 | Problem | solve | </code></pre> <hr> <h2>UPDATE 1</h2> <p>To get the count of messages for each ticket, you can simply include <code>COUNT(history_id) AS sum_message</code> in the subquery like this:</p> <pre><code>SELECT t.ticket_id, ticket_desc, ht.status, ht2.sum_message FROM ticket AS t INNER JOIN history_ticket ht ON t.ticket_id = ht.ticket_id INNER JOIN ( SELECT ticket_id, MAX(history_id) maxid, COUNT(history_id) AS sum_message FROM history_ticket GROUP BY ticket_id ) AS ht2 ON ht.history_id = ht2.maxid; </code></pre> <h2><a href="http://sqlfiddle.com/#!2/0d086/5" rel="nofollow">Updated SQL Fiddle Demo</a></h2> <p>This will give you:</p> <pre><code>| TICKET_ID | TICKET_DESC | STATUS | SUM_MESSAGE | --------------------------------------------------- | 1 | software | process | 1 | | 2 | hardware | solve | 1 | | 3 | Problem | solve | 2 | </code></pre> <hr> <h2>Update 2</h2> <p>If you want to select names for the ids <code>divisi_id</code>, for simple values, you can use the <code>CASE</code> expression for this:</p> <pre><code>SELECT t.ticket_id, ticket_desc, CASE WHEN t.divisi_id = 101 THEN 'Divisi A' WHEN t.divisi_id = 102 THEN 'Divisi B' END AS 'Divisi', ht.status, ht2.sum_message FROM ticket AS t INNER JOIN history_ticket ht ON t.ticket_id = ht.hticket_id INNER JOIN ( SELECT hticket_id, MAX(history_id) maxid, COUNT(history_id) AS sum_message FROM history_ticket GROUP BY hticket_id ) AS ht2 ON ht.history_id = ht2.maxid; </code></pre> <h2><a href="http://sqlfiddle.com/#!2/eba04/6" rel="nofollow">Updated SQL Fiddle Demo</a></h2> <p>This will give you:</p> <pre><code>| TICKET_ID | TICKET_DESC | DIVISI | STATUS | SUM_MESSAGE | -------------------------------------------------------------- | 1 | software | Divisi A | process | 1 | | 2 | hardware | Divisi B | solve | 1 | | 3 | Problem | Divisi A | solve | 2 | </code></pre> <p>For multiple values, you can put them in a temp table, or you can select them in a subquery and join the table to get the name like this:</p> <pre><code>SELECT t.ticket_id, ticket_desc, d.Divisi, ht.status, ht2.sum_message FROM ticket AS t INNER JOIN history_ticket ht ON t.ticket_id = ht.hticket_id INNER JOIN ( SELECT hticket_id, MAX(history_id) maxid, COUNT(history_id) AS sum_message FROM history_ticket GROUP BY hticket_id ) AS ht2 ON ht.history_id = ht2.maxid INNER JOIN ( SELECT 101 AS divisi_id, 'Divisi A' AS Divisi UNION ALL SELECT 102 , 'Divisi B' ... -- here you put other values or you can join a temp table instead ) AS D ON t.divisi_id = D.divisi_id; </code></pre> <h2><a href="http://sqlfiddle.com/#!2/eba04/7" rel="nofollow">Updated SQL Fiddle Demo</a></h2>
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    1. POPHP MYSQL query a join table for to get last row for parent table query
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    1. USMahmoud Gamal
    1. USMahmoud Gamal
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    1. POPHP MYSQL query a join table for to get last row for parent table query
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    1. COSorry i'm newbie for mysql query. But i try to implemented your scheme on my database. And i still confuse :( I update the question, please help. Thank you.
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      1. USHafiz
    2. CO@Hafiz - Why are you confused? Have you tried it? If it doesn't work can you please post the errors you got if any? or you can try to edit [the demo](http://sqlfiddle.com/#!2/0d086/3) example to explain the issue.
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    3. CO@Hafiz OK, See my edit, I think it is count of messages not the sum.
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