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    <p>The <code>for</code> enumeration is going to go over <em>every</em> member of the object you passed it. In this case an array, which happens to have functions as members as well as the elements passed.</p> <p>You could re-write your for loop to check if <code>typeof stypes[t] == "function"</code> or yada yada. But IMO you are better off just modifying your looping to only elements.. </p> <pre><code>for(var i = 0, t; t = stypes[i]; ++i){ if (t != x) { alert(t); } } </code></pre> <p>Or </p> <pre><code>for(var i = 0; i &lt; stypes.length; ++i){ if (stypes[i] != x) { alert(stypes[i]); } } </code></pre> <p>I wanted to migrate my last comment up to the answer to add the notice of the a caveat for the first type of loop.</p> <p>from <a href="https://developer.mozilla.org/En/A_re-introduction_to_JavaScript" rel="noreferrer">Simon Willison's "A re-introduction to JavaScript"</a>..</p> <pre><code>for (var i = 0, item; item = a[i]; i++) { // Do something with item } </code></pre> <blockquote> <p>Here we are setting up two variables. The assignment in the middle part of the for loop is also tested for truthfulness - if it succeeds, the loop continues. Since i is incremented each time, items from the array will be assigned to item in sequential order. The loop stops when a "falsy" item is found (such as undefined).</p> <p>Note that this trick should only be used for arrays which you know do not contain "falsy" values (arrays of objects or DOM nodes for example). If you are iterating over numeric data that might include a 0 or string data that might include the empty string you should use the i, j idiom instead.</p> </blockquote>
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    1. POJavaScript Array Iteration returning more than values
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    1. COAny explanation for the downvote, I'm very interested in the reason for it.
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      1. USQuintin Robinson
    2. COJust to add to your correct answer: `"for..in"` crawls up the `Array.prototype chain`. See http://www.ecma-international.org/publications/standards/Ecma-262.htm (Sec 12.6.4), while a standard `for` loop does not. Also, the order of items iterated with "`for..in`" is not guaranteed. A standard `for` loop is.
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    3. COThis worked for me. I've upvoted you back to zero. I am not familiar with this syntax in for() for(var i = 0, t; What is that called?
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