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POJava help to convert UDP packet to int
 

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  1. POJava help to convert UDP packet to int
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    <p>I'm receiving an UDP packet (in which format I don't know, I think UTF-16 -little endian-), only thing that I know is the following doc. directly from the developers page:</p> <blockquote> <p>The master servers each respond by sending FF FF FF FF 73 0A followed by a (relatively) unique 4-byte "challenge" number.</p> </blockquote> <p>So this is how I'm receiving the packet:</p> <pre><code>byte[] buff = new byte[64]; DatagramPacket packet = new DatagramPacket(buff, buff.length); socket.receive(packet); </code></pre> <p>Packet was received, everything is Okay, but now I'm stuck. I need that 4 byte integer. I must split the buffer or... I don't know what to do.</p> <p>This is the received data:</p> <pre><code>˙˙˙˙s Ň?t </code></pre> <p>I tried to convert to hex but the output is very interesting:</p> <blockquote> <p>-0000000000000000000000000008cf52df7c08c</p> </blockquote> <p>Method to convert:</p> <pre><code>public String toHex(String arg) throws UnsupportedEncodingException { return String.format("%040x", new BigInteger(arg.getBytes("UTF-16LE"))); } </code></pre> <p>Than I tried to convert hex to string (from the method above) and the result is much more interesting (sorry I can't copy paste, something goes wrong), anyway the method used to convert hex to string is:</p> <pre><code>public String hexToString(String hex){ StringBuilder output = new StringBuilder(); for (int i = 0; i &lt; hex.length(); i+=2) { String str = hex.substring(i, i+2); output.append((char)Integer.parseInt(str, 16)); } return new String(output); } </code></pre> <p>So with all that said, I'm stuck. I don't know what am I supposed to do. Am I need to split the UDP packet in to pieces or...?</p>
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    1. COThe complement of 00008CF5 is FFFF730A ... There is no UTF of any kind here, just binary. The integer is ~2DFC078C.
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