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    <p>This should do it:</p> <pre><code>var validTags = [{"tag":"tag1"}, {"tag":"tag2"}]; var items = [{"id":123456, "tag":"tag1"}, {"id":123456, "tag":"tag2"}, {"id":7890, "tag":"tag1"}]; var actualTags = validTags.map(function(obj){return obj.tag}), comparableTags = actualTags.sort().join(" "); var tagsById = items.reduce(function(map, item) { if (item.id in map) map[item.id].push(item.tag); else map[item.id] = [ item.tag ]; return map; }, {}); var result = []; for (var id in tagsById) { var tags = tagsById[id].sort().join(" "); if (comparableTags == tags) // Yai, array comparison by content! result.push({id: id, tag:tags}); } return result; </code></pre> <p>If you were using <a href="http://underscorejs.org/" rel="nofollow">Underscore</a>, you could use <a href="http://underscorejs.org/#pluck" rel="nofollow"><code>pluck</code></a> instead of the <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/Map" rel="nofollow"><code>map</code></a> and <a href="http://underscorejs.org/#groupBy" rel="nofollow"><code>groupBy</code></a> instead of the <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/Reduce" rel="nofollow"><code>reduce</code></a>; in short:</p> <pre><code>var comparableTags = _.pluck(validTags, "tag").sort().join(" "); return _.chain(items).groupBy("id").map(function(id, tags) { return {id:id, tag:tags.sort().join(" "); }.filter(function(obj) { return obj.tag == comparableTags; }).value(); </code></pre>
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    1. POImplementing an array intersection with JSON values
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    1. COAh ok brill (I am using underscore :D). With the code above, if I was to have var validTags = [{"tag":"tag1"}]; would it be possible to return the items that contain tag1, even if they also contain tag2? So at the moment if it was just "tag1" in valid tags I get back ID 7890, but could I also get back ID 123456 (because it does have tag1 assigned to it)?
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    2. COThen don't use my string comparison, but something like `if (_difference(actualTags, obj.tags).length == 0)` (where `obj.tags` is still an array). Not sure if there is a more expressive and performant way
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    3. COThanks for your help
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