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POConverting large decimal input to hexadecimal output in a 256 bit array in C
 

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  1. POConverting large decimal input to hexadecimal output in a 256 bit array in C
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    <p>I have a written a code to convert a large number based on the use input to hexadecimal number. However when the result is printed, the only part of the number is converted to hexadecimal and there are other random values in the array.</p> <p>for example: decimal = 1234567891012 ---- the hexa would = 00 00 00 02 00 00 00 65 00 6b 42 48 71 fb 08 44</p> <p>the last four vales (<code>71 FB 08 44</code>) are the correct hexadecimal value, but the others are incorrect</p> <p>i am using uint8_t buf[];</p> <p>Code:</p> <pre><code>int main() { uint8_t buf[] = {0}; long int i,a; printf("Enter Number: "); scanf("%d", &amp;buf); printf("\n"); printf("Input #: "); /* put a test vector */ for (i = 15; i &gt;= 0; i--) { printf("%02x ", buf[i]); } printf("\n\n"); printf("\n\n"); printf("%d\n",sizeof(buf)); system("pause"); return 0; } </code></pre>
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    1. COPlease post your code.
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    2. COfor set?? what does that mean?
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    3. CO`random values` usually means you didn't initialize your array to something valid, so it's garbage.
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      1. USMike
 

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