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POWhy phpunit doesn't run __destruct() in mocked class and how to force it?
 

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  1. POWhy phpunit doesn't run __destruct() in mocked class and how to force it?
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    <p>Code will explain everything:</p> <pre><code>&lt;?php class ATest extends PHPUnit_Framework_TestCase { public function testDestructorOnOriginalClass() { $a = new A(); // It unset($a); // works echo " great!"; // great! $this-&gt;expectOutputString('It works great!'); } public function testDestructorOnMockedClass() { $a = $this-&gt;getMock('A', array('someNonExistingMethod')); // It unset($a); // works echo " great!"; // great! $this-&gt;expectOutputString('It works great!'); } } class A { public function __construct() { echo "It"; } public function __destruct() { echo " works"; } } </code></pre> <p>and the output:</p> <pre><code># phpunit ATest.php PHPUnit 3.7.13 by Sebastian Bergmann. .F Time: 0 seconds, Memory: 3.50Mb There was 1 failure: 1) ATest::testDestructorOnMockedClass Failed asserting that two strings are equal. --- Expected +++ Actual @@ @@ -'It works great!' +'It great! works' FAILURES! Tests: 2, Assertions: 2, Failures: 1. </code></pre> <p>As you can see in the second test it prints <code>works</code> in wrong order, probably because phpunit stores reference to mock somewhere and <code>__destruct()</code> is called at the end of test... Ok I've already checked <code>getMock()</code> method and indeed it stores reference to mocked object (<code>$this-&gt;mockObjects[] = $mockObject;</code>) efficiently blocking object from being destructed and so <code>__destructor()</code> is never called.</p> <pre><code>/** * Returns a mock object for the specified class. * * @param string $originalClassName * @param array $methods * @param array $arguments * @param string $mockClassName * @param boolean $callOriginalConstructor * @param boolean $callOriginalClone * @param boolean $callAutoload * @param boolean $cloneArguments * @return PHPUnit_Framework_MockObject_MockObject * @throws PHPUnit_Framework_Exception * @since Method available since Release 3.0.0 */ public function getMock($originalClassName, $methods = array(), array $arguments = array(), $mockClassName = '', $callOriginalConstructor = TRUE, $callOriginalClone = TRUE, $callAutoload = TRUE, $cloneArguments = FALSE) { $mockObject = PHPUnit_Framework_MockObject_Generator::getMock( $originalClassName, $methods, $arguments, $mockClassName, $callOriginalConstructor, $callOriginalClone, $callAutoload, $cloneArguments ); $this-&gt;mockObjects[] = $mockObject; return $mockObject; } </code></pre> <p>So the question is - is there a way to prevent this? Ignoring <code>__destruct()</code> when it should be called is I think bad limitation.</p>
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    1. USKamil Dziedzic
    1. USKamil Dziedzic
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      1. POWhy phpunit doesn't run __destruct() in mocked class and how to force it?
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      1. VTUpMod
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    1. COIs this a theoretical question or do you really rely on destructor behaviour of dependent classes in your SUT? If so, this might be a sign of bad design. This problem should not really *be* a problem.
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      1. POWhy phpunit doesn't run __destruct() in mocked class and how to force it?
      1. USFabian Schmengler
    2. COCurrently I try to mock PDO class and mimic it's behaviour to end database connection when object is destroyed (and there is no other way to close connection) - so this isn't class I can change (except extending it, and this is what i probably will go for if mocking with `getMock()` won't work).
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      1. POWhy phpunit doesn't run __destruct() in mocked class and how to force it?
      1. USKamil Dziedzic
    3. COOkay, PDO is a special case anyway. If you want to mock it, you *need to* extend it first and override the constructor, otherwise the MockBuilder cannot instantiate it at all (assuming you don't want an actual connection, otherwise you would not mock it, would you?)
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      1. USFabian Schmengler
 

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