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POIsolating Ruby methods from overriding in subclasses? (like Java's private methods)
 

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  1. POIsolating Ruby methods from overriding in subclasses? (like Java's private methods)
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    <p>In Ruby, I'd like to acheive something like this Java sample:</p> <pre><code>class A { private void f() { System.out.println("Hello world"); } public void g() { f(); } } class B extends A { public void f() { throw new RuntimeException("bad guy");} } public class Try { public static void main(String[] args) { new B().g();} } </code></pre> <p>This will print "Hello world" in Java, but the straight Ruby transcript:</p> <pre><code>class A def g; f; end private def f; puts "Hello world"; end end class B &lt; A def f; raise "bad guy"; end end B.new.g # want greet </code></pre> <p>will of course raise a bad guy - due to differences in method lookup mechanism (I realise the meaning of 'private' is very different between these languages)</p> <p>Is there any way to achieve a similar effect? I don't really care about visibility, would actually prefer all public methods here. My goal is simply to isolate a method in the superclass from overriding in subclasses (which would break the other base methods).</p> <p>I guess if there is a solution, that would work with modules/includes, too?</p> <pre><code>module BaseAPI def f; puts "Hello world"; end def g; f; end; end module ExtAPI include BaseAPI # some magic here to isolate base method :f from the following one? def f; raise "bad guy"; end # could actually be something useful, but interfering with base 'g' end include ExtAPI g # want greet </code></pre> <hr> <p>Follow-up: this looks to be the rare case where something is possible with Java but not with Ruby :-/</p>
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    1. COCould you clean that second one up?
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    2. CODone (just for the record).
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