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    <p>Yes. I'll try and answer your case by showing how I did it, and I'll show an example for your case below my code sample.</p> <p>Basically, to accomplish this you have to keep track which position your Fragments have. Below is the implementation I used for my <code>FragmentPagerAdapter</code>, which uses an ArrayList as its data source.</p> <pre class="lang-java prettyprint-override"><code>public class MyFragmentPagerAdapter extends FragmentPagerAdapter { private HashMap&lt;Long, Fragment&gt; mItems = new HashMap&lt;Long, Fragment&gt;(); private ArrayList&lt;MyObject&gt; dataset; public MyFragmentPagerAdapter(ArrayList&lt;MyObject&gt; objects) { this.dataset = objects; } @Override public int getCount() { return dataset.size(); } @Override public Fragment getItem(int position) { long id = getItemId(position); if(mItems.get(id) != null) { // caching to prevent multiple instances of the same fragment // for the same position/id return mItems.get(id); } Fragment f = Fragment.newInstance(); mItems.put(id, f); return f; } @Override public long getItemId(int position) { // return a unique id return dataset.get(position).getUniqueId(); } @Override public int getItemPosition(Object object) { /* * Purpose of this method is to check whether an item in the adapter * still exists in the dataset and where it should show. * For each entry in dataset, request its Fragment. * * If the Fragment is found, return its (new) position. There's * no need to return POSITION_UNCHANGED; ViewPager handles it. * * If the Fragment passed to this method is not found, remove all * references and let the ViewPager remove it from display by * by returning POSITION_NONE; */ Fragment f = (Fragment) object; for(int i = 0; i &lt; getCount(); i++) { Fragment item = (Fragment) getItem(i); if(item.equals(f)) { // item still exists in dataset; return position return i; } } // if we arrive here, the data-item for which the Fragment was created // does not exist anymore. // Also, cleanup: remove reference to Fragment from mItems for(Map.Entry&lt;Long, MainListFragment&gt; entry : mItems.entrySet()) { if(entry.getValue().equals(f)) { mItems.remove(entry.getKey()); break; } } // Let ViewPager remove the Fragment by returning POSITION_NONE. return POSITION_NONE; } } </code></pre> <p>Now if you remove an item from the dataset (<code>this.dataset</code>) and call <code>notifyDataSetChanged()</code> on your instance of <code>MyFragmentPagerAdapter</code>, it will remove the item from the ViewPager (even if it's currently being viewed).</p> <p>Let's say <code>this.dataset</code> contains 5 items, and you want to move #2 to the end of the ViewPager. To accomplish this, you'll have to position item#2 to the end of your datasource (either via <code>Collection.Sort</code> or some other way). I'll just show you the easy way.</p> <pre class="lang-java prettyprint-override"><code>ArrayList&lt;MyObject&gt; list = new ArrayList&lt;&gt;(); MyFragmentPagerAdapter adapter = new MyFragmentPagerAdapter(list); viewpager.setAdapter(adapter); ... MyObject item = list.get(2); list.remove(item); list.add(item); // now it's positioned at the end of the list adapter.notifyDataSetChanged(); // voilá, that should do the trick! </code></pre> <p><code>adapter.notifyDataSetChanged()</code> eventually calls <code>viewpager.dataSetChanged()</code>, which in turn calls <code>adapter.getItemPosition(..)</code> on each of its pages. The result of that method call determines if and where the page (Fragment in this case) will show up.</p>
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    1. POAndroid ViewPager: Move any page to end programatically?
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    1. POAndroid ViewPager: Move any page to end programatically?
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    1. COVery comprehensible. Any reason why you aren't using a FragmentStatePagerAdapter with this implementation? Will your mItems list make the large-scale class lose all reasons for it's usability?
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    2. COThis also didn't seem to help me. I'm removing items, altogether. Whenever I went to the next item, removed the previous item, it would swipe but mid-swipe change the next item to be the item after that. Visually: A, B, C items in adapter View A, Swipe to B. Begin removing A, mid swipe to B, Flash to C.
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    3. COYes, this is expected. If you remove A, B will be pos==0, and C pos==1. Your current item (`viewPager.setCurrentItem(int)`) is set to 1 when swiping from A to B. When you remove A the current position will still be 1, which means the `ViewPager` will jump to C. You can correct this by setting `viewPager.setCurrentItem(adapter.getItemPosition(fragment-B))` when you remove A.
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