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    <p>I have done some research (over <em>several</em> hours) and have found some solutions to my issues!</p> <p><strong>3:</strong> Yes, There is a way to have the clients communicate with each other, <em>they just have to use the server!</em> You have to initialize an infinite loop on the server side, which will receive data and send it. This is how I solved the issue:</p> <pre><code> while True: #Receiving from client data = conn.recv(1024) if not data: break conn.sendall(data) print data #To come out of the loop conn.close() </code></pre> <p>This program is part of a definition called <strong>clientthread</strong> which initializes all connections with clients. The "Actual" loop carries on the rest of the thread:</p> <pre><code> while True: #Wait to accept a connection - blocking call conn, addr = s.accept() #display client information (IP address) print 'Connected with ' + addr[0] + ':' + str(addr[1]) #Start new thread takees 1st argument as a function name to be run, second #is the tuple of arguments to the function start_new_thread(clientthread ,(conn,)) </code></pre> <p><strong>4:</strong> Yes, it will work between OS's. Sockets are <em>independent</em> of the platform. </p> <p><strong>6:</strong> That line of code is actually quite simple. The line <code>print channel.recv ( 100 )</code> tells the server to print the user input, up to 100 characters. The next line, <code>channel.send ( 'Green-eyed monster.' )</code> is simply telling the server to send out a message, <code>Green-eyed monster</code> to the client. </p> <p><strong>7:</strong> That error occurs because you cannot have more than one socket open per port. I would suggest using a line such as <code>s.close()</code> or <code>sys.exit()</code> at the end of your code, to close the port. Or you can simply choose another one!</p> <p><strong>8:</strong> There are some great tutorials out on the internet. One that teaches you the basics of sockets is <a href="http://www.binarytides.com/python-socket-programming-tutorial/1/" rel="nofollow">this</a>. Telnet was really confusing for me, so I discovered that in conjunction with <a href="http://www.devshed.com/c/a/Python/Sockets-in-Python/2/" rel="nofollow">this</a> client one can create a customized client which is in fact much better. </p> <p>If you have any questions, feel free to comment and I will try to answer.</p>
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