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    <p>If you don't want to write Java Code for this - I think using the command line HDFS API is your best bet: </p> <p><a href="http://hadoop.apache.org/docs/r0.20.0/hdfs_shell.html#mv" rel="noreferrer"><code>mv</code> in Hadoop</a></p> <p><code>hadoop fs -mv URI [URI …] &lt;dest&gt;</code> </p> <p>You can get the paths using a small one liner:</p> <pre><code>% hadoop fs -ls /user/foo/bar | awk '!/^d/ {print $8}' /user/foo/bar/blacklist /user/foo/bar/books-eng ... </code></pre> <p>the <code>awk</code> will remove directories from output..now you can put these files into a variable:</p> <pre><code>% files=$(hadoop fs -ls /user/foo/bar | awk '!/^d/ {print $8}') </code></pre> <p>and rename each file..</p> <pre><code>% for f in $files; do hadoop fs -mv $f $f.lzo; done </code></pre> <p>you can also use <code>awk</code> to filter the files for other criteria. This should remove files that match the regex <code>nolzo</code>. However it's untested. But this way you can write flexible filters.</p> <pre><code>% files=$(hadoop fs -ls /user/foo/bar | awk '!/^d|nolzo/ {print $8}' ) </code></pre> <p>test if it works with replacing the <code>hadoop</code> command with <code>echo</code>:</p> <pre><code>$ for f in $files; do echo $f $f.lzo; done </code></pre> <p>Edit: Updated examples to use <code>awk</code> instead of <code>sed</code> for more reliable output.</p> <p>The "right" way to do it is probably using the <a href="http://hadoop.apache.org/docs/current/api/org/apache/hadoop/fs/FileSystem.html" rel="noreferrer">HDFS Java API</a> .. However using the shell is probably faster and more flexible for most jobs. </p>
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    1. COthis is definitely helpful, although your cut approach doesn't work predictably, and the sed gives me errors
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    2. COYes it's far from perfect. I guess using `awk` or coming up with something more sophisticated for parsing `hadoop fs -ls` should work through...
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    3. COI updated the answer to use `awk`. Should work better now. Time to learn `awk` for me ;)
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