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POHow to separate arrays into variables
 

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  1. POHow to separate arrays into variables
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    <p>I've tried to look this up, but I'm not quite getting an answer that pertains directly to what I'm doing. I'm trying to retrieve values from a database that were previously submitted. I want to use these values to locate filepaths on the server and use the fillepath information to display the files. To do this, I need to separate the array that i have here. How would I separate this array?</p> <pre><code>$code = $_POST['codeInput']; $code = htmlspecialchars($code); $submitCodes = "SELECT story,video FROM `storycodes` WHERE `code` = $codeInput"; $files = mysql_fetch_array($submitCodes); mysql_close($con); print_r(array_values($files)); </code></pre> <p>I appreciate any help guys. Ideally I would like to get a variable like $story or $storyPath and $video or $videoPath I need the video as a variable so I can play it with a video player.</p> <p>EDIT: I changed from mysql to mysqli and I'm getting all of these errors now that I can't seem to fix. I have the result set and it says I don't.</p> <p>Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, boolean given in /home/content/98/10339998/html/scripts/stories.php on line 26</p> <p>I think this warning should fix itself once the array gets sorted out:</p> <p>Warning: extract() expects parameter 1 to be array, null given in /home/content/98/10339998/html/scripts/stories.php on line 28</p> <p>Warning: mysqli_free_result() expects parameter 1 to be mysqli_result, boolean given in /home/content/98/10339998/html/scripts/stories.php on line 30</p> <pre><code>$con = mysqli_connect("storycodes.db.10339998.hostedresource.com",$username,$password); if (!$con) { die('Could not connect: ' . mysql_error()); } mysqli_select_db($con, "storycodes"); $code = $_POST['codeInput']; $code = htmlspecialchars($code); $query = "SELECT story,video FROM `storycodes` WHERE `code` = $codeInput"; $result = mysqli_query($con, $query); $row = mysqli_fetch_assoc($result); extract($row); mysqli_free_result($result); mysqli_close($con); echo $story . $video; </code></pre>
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    1. CODon't use the `mysql_*` functions for new projects. They are deprecated in 5.5 and will be removed soon. Consider `PDO` or `mysqli_*` functions instead.
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