StackOverflow2013

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PO
primarykey
Id
14667862
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
0
CommunityOwnedDate
CreationDate
2013-02-02T23:51:37.930
FavoriteCount
0
LastActivityDate
2013-02-02T23:59:09.443
LastEditDate
2013-02-02T23:59:09.443
LastEditorUserId
784338
OwnerUserId
784338
ParentId
14667662
PostTypeId
2
Score
3
ViewCount
0
LastEditorDisplayName
text
Body
Haskell is a bit unusual in this way. Yes you can't divide to integers together but it's rarely a problem. The reason is that if you look at the <code>Num</code> typeclass, there's a function <code>fromIntegral</code> this allows you to convert literals into the appropriate type. This with type inference alleviates 99% of the cases where it'd be a problem. Quick example: <pre><code>newtype Foo = Foo Integer deriving (Show, Eq) instance Num Foo where fromInteger _ = Foo 0 negate = undefined abs = undefined (+) = undefined (-) = undefined (*) = undefined signum = undefined </code></pre> Now if we load this into GHCi <pre><code>*> 0 :: Foo Foo 0 *> 1 :: Foo Foo 0 </code></pre> So you see we are able to do some pretty cool things with how GHCi parses a raw integer. This has a lot of practical uses in DSL's that we won't talk about here. Next question was how to get from a Double to an Integer or vice versa. There's a function for that. In the case of going from an Integer to a Double, we'd use <code>fromInteger</code> as well. Why? Well the type signature for it is <pre><code>(Num a) => Integer -> a </code></pre> and since we can use <code>(+)</code> with Doubles we know they're a <code>Num</code> instance. And from there it's easy. <pre><code>*> 0 :: Double 0.0 </code></pre> Last piece of the puzzle is <code>Double -> Integer</code>. Well a brief search on Hoogle shows <pre><code>truncate floor round -- etc ... </code></pre> I'll leave that to you to search.
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1. POHaskell Type Coercion
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1. USjozefg
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1. USjozefg
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