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2013-01-31T23:33:58.337
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You don't need to create a separate email message for each recipient; just send a single message with multiple recipients: <pre><code>def send_mail(send_from,send_to, subject, text, files=[], server = "localhost"): msg = MIMEMultipart() msg['From'] = send_from msg['To'] = COMMASPACE.join(send_to) # ... server = smtplib.SMTP(server) server.sendmail(send_from, send_to, msg.as_string()) server.close() </code></pre> This is almost identical to the example "Here’s an example of how to send a MIME message containing a bunch of family pictures that may be residing in a directory" in the <a href="http://docs.python.org/2/library/email-examples.html" rel="nofollow">docs</a>. (If you don't want each person to see the other's addresses, you can make them all <code>BCC</code>s instead of <code>To</code>s.) If you're more interested in what's wrong with your original code, than with how to do it properly, there are two immediately visible problems: <ol> <li>You're <code>join</code>ing each address, as Vader explains.</li> <li>You're passing a single address as a string as the second argument to <a href="http://docs.python.org/2/library/smtplib.html#smtplib.SMTP.sendmail" rel="nofollow"><code>SMTP.sendmail</code></a>, but the second argument is a sequence of addresses. To fix that, use <code>[s]</code> instead of <code>s</code>, as most of the examples do.</li> </ol> Both of these are caused by the same confusion, treating each address as a list of addresses. You may have additional errors caused by the same problem.
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1. POEncountering an error when I try to send an email to multiple people in python
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1. POEncountering an error when I try to send an email to multiple people in python
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1. COThanks man. I just took out my for loop and used the list in the sendmail and it worked fine. Kinda proud I figured it out before I checked here. :) Thanks for your assistance.
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