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POpass a hidden input value to php
 

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  1. POpass a hidden input value to php
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    <p>i found this code to upload profile image, </p> <p><a href="http://www.phpdevblog.eu/2011-04/combined/jquery-ajax-and-php-based-profile-image-upload-without-reloading-the-page.html#comments" rel="nofollow">http://www.phpdevblog.eu/2011-04/combined/jquery-ajax-and-php-based-profile-image-upload-without-reloading-the-page.html#comments</a></p> <p>everything are fine. but i want to set a name file = user_id</p> <p>how i pass the input hidden user_id value to the php upload file process?</p> <pre><code>var uploadURL = "processupload.php"; $(document).ready(function(){ $('a#uploadFile').file(); $('a#delete').click(function(){ $('input#profileImageFile').val(""); $('img#profileImage').attr("src","/images/styles/profileBlank.jpg"); $('div#messageBox').html("Image deleted !"); $('div#messageBox').attr("class","success"); $('a#delete').hide(); }); $('input#uploadFile').file().choose(function(e, input) { input.upload(uploadURL, function(res) { if (res=="invalid"){ $('div#messageBox').attr("class","error"); $('div#messageBox').html("Invalid extension !"); }else{ $('div#messageBox').attr("class","success"); $('div#messageBox').html("Imagen cargada !"); $('img#profileImage').attr("src","/images/avatars/"+res); $('input#profileImageFile').val(res); $('a#delete').show(); $(this).remove(); } }, ''); }); }); </code></pre> <p>html</p> <pre><code>&lt;div class="imageContainer"&gt; &lt;img alt="" src="/images/avatars/&lt;?php echo $row_rs_user['user_image']; ?&gt;" width="150" height="150" id="profileImage"&gt; &lt;a href="#" id="uploadFile" title="Upload"&gt;&lt;img alt="" src="/images/styles/upload.jpg"&gt;&lt;/a&gt; &lt;a href="#" id="delete" title="Delete" style="display:none;position:relative;z-index:999999;"&gt;&lt;img alt="" src="/images/styles/delete.jpg"&gt;&lt;/a&gt; &lt;input type="hidden" name="user_id" value="&lt;?php echo $row_rs_user['user_id']; ?&gt;"&gt; &lt;div id="messageBox"&gt;&lt;/div&gt; &lt;/div&gt; </code></pre> <p>PHP upload process</p> <pre><code>if(isset($_POST)) { . . . . </code></pre>
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    1. COSending a user_id via POST is not a good idea. Just use the user id from your session (I guess users must be logged in to have a user_id?), thats a lot safer.
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    2. COGood idea... problem solved. THANKS
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      1. USosanjur
 

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