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    <p>Use the built in <code>isinstance</code> and <code>all</code> functions, along with list slicing.</p> <pre><code>if all(isinstance(i, int) for i in mylist[-3:]): # do something else: # do something else </code></pre> <ul> <li><code>all</code> checks if all elements in the given iterable evaluate to <code>True</code>.</li> <li><code>isinstance</code> checks if the given object is an instance of the second parameter</li> <li><code>mylist[-3:]</code> returns the last three elements of <code>mylist</code></li> </ul> <p>Also, if you're using Python 2 and have very large numbers in your list, check for the <code>long</code> (long integer) type as well.</p> <pre><code>if all(isinstance(i, (int, long)) for i in mylist[-3:]): pass </code></pre> <p>This prevents numbers like <code>10**100</code> from breaking the condition.</p> <p>If, however, your last three elements are strings, you have two options.</p> <p>If you know none of the numbers are exceedingly large, you can use the <code>isdigit</code> string method.</p> <pre><code>if all(i.isdigit() for i in mylist[-3:]): pass </code></pre> <p>However, if they can be very large (around or over <code>2**31</code>), use a <code>try/except</code> block and the built in <code>map</code> function.</p> <pre><code>try: mylist[-3:] = map(int, mylist[-3:]) # do stuff except ValueError: pass </code></pre> <ul> <li><code>try</code> defines the block of code to execute</li> <li><code>except Exception</code> catches the given exception and handles it without raising an error (unless told to do so)</li> <li><code>map</code> applies a function to each element of an iterable and returns the result.</li> </ul>
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    1. POHow to check last three elements from a python list - whether they are integer?
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    1. COmissing `int` in the `isisntance` call
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    2. CO@root Yeah, forgot to put that in
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    3. COShould be `isinstance(i, (int, long))`
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