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POSimple .txt File-Reading with ifstream
 

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  1. POSimple .txt File-Reading with ifstream
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    <p>Just what is probably a basic question for something I haven't been able to figure out all day. Here's a snippet of code in C++:</p> <pre><code>Escape::Escape(std::string filename) { std::ifstream file; file.open(filename.c_str()); if (file.is_open()) { file &gt;&gt; gridWidth &gt;&gt; gridHeight &gt;&gt; nKeys; std::cout &lt;&lt; "gridWidth = " &lt;&lt; gridWidth &lt;&lt; std::endl; std::cout &lt;&lt; "gridHeight = " &lt;&lt; gridHeight &lt;&lt; std::endl; std::cout &lt;&lt; "nKeys = " &lt;&lt; nKeys &lt;&lt; std::endl; /* irrelevant code below */ </code></pre> <p>Basically I want this code to read the first three integers of a text file and save them into the variables gridWidth, gridHeight, and nKeys. These are private integers of a class called "Escape". Here are the first few lines of the text file:</p> <pre><code>8 8 1 BUL--/EUR--/BUL--/BU---/BU---/BU---/BU---/BUR--/ (more text below) </code></pre> <p>And here is some sample output of this code:</p> <pre><code>gridWidth = 107764358 gridHeight = -991553646 nKeys = 0 </code></pre> <p>On running this code multiple times, <code>gridWidth</code> and <code>gridHeight</code> are always junk and nKeys is always 0. Any ideas as to what I am doing wrong?</p> <p><strong>EDIT: The problem was with the filename I passed to <code>file.open()</code>. I passed in the relative filename which, although openable, was not linkable to the ifstream. The problem was resolved by using the text file's absolute filename instead.</strong></p>
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    1. COtest the file by piping it to `cout` really quick
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