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The easiest way to redirect to the last page, is to use the URI directly: <pre><code><g:link controller="user" action="logout" params="[targetUri: (request.forwardURI - request.contextPath)]">Logout</g:link> </code></pre> (<code>request.forwardURI</code> is the complete URL as displayed in the browser, while <code>request.contextPath</code> is the URL part representing the app context, eg. "<a href="http://localhost:8080/yourApp" rel="nofollow noreferrer">http://localhost:8080/yourApp</a>" - thus, the result of removing the context path from the forward URI is the app-relative URI, eg. "/mycontroller/myaction") In your logout action simply redirect to this URI: <pre><code>def targetUri = params.targetUri ?: "/" redirect(uri: targetUri) </code></pre> AFAIK, using the referrer is not entirely safe, because this relies on the user agent (browser) to append the referrer HTTP header (which may have been disabled). As to your 2nd question: Grails automatically interprets list or map attribute values in GSPs as Groovy expressions. So, this <pre><code><g:link controller="user" action="logout" params="[currentController: params.controller, currentAction: params.action]">Logout</g:link> </code></pre> is equivalent to <pre><code><g:link controller="user" action="logout" params="${[currentController: params.controller, currentAction: params.action]}">Logout</g:link> </code></pre> and wrapping parts of this expression again in <code>${...}</code> seems to confuse the GSP compiler. Hope this helps.
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1. POHow to redirect to the last visited page in Grails app?
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1. USDaniel Rinser
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1. COHi Daniel, Thank you very much for your aswer. You helped me a lot !!
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 USfabien7474

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