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POC++ Replace string to char[]
 

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    <p>I have the following c++ program that multiple 2 large numbers :</p> <pre><code>#include &lt;iostream&gt; #include &lt;string&gt; #define OVERFLOW 2 #define ROW b_len #define COL a_len+b_len+OVERFLOW using namespace std; int getCarry(int num) { int carry = 0; if(num&gt;=10) { while(num!=0) { carry = num %10; num = num/10; } } else carry = 0; return carry; } int num(char a) { return int(a)-48; } string mult(string a, string b) { string ret; int a_len = a.length(); int b_len = b.length(); int mat[ROW][COL]; for(int i =0; i&lt;ROW; ++i) { for(int j=0; j&lt;COL; ++j) { mat[i][j] = 0; } } int carry=0, n,x=a_len-1,y=b_len-1; for(int i=0; i&lt;ROW; ++i) { x=a_len-1; carry = 0; for(int j=(COL-1)-i; j&gt;=0; --j) { if((x&gt;=0)&amp;&amp;(y&gt;=0)) { n = (num(a[x])*num(b[y]))+carry; mat[i][j] = n%10; carry = getCarry(n); } else if((x&gt;=-1)&amp;&amp;(y&gt;=-1)) mat[i][j] = carry; x=x-1; } y=y-1; } carry = 0; int sum_arr[COL]; for(int i =0; i&lt;COL; ++i) sum_arr[i] = 0; for(int i=0; i&lt;ROW; ++i) { for(int j=COL-1; j&gt;=0; --j) { sum_arr[j] += (mat[i][j]); } } int temp; for(int i=COL-1; i&gt;=0; --i) { sum_arr[i] += carry; temp = sum_arr[i]; sum_arr[i] = sum_arr[i]%10; carry = getCarry(temp); } for(int i=0; i&lt;COL; ++i) { ret.push_back(char(sum_arr[i]+48)); } while(ret[0]=='0'){ ret = ret.substr(1,ret.length()-1); } return ret; } void printhuge(string a) { cout&lt;&lt;"\n"; for(string::iterator i = a.begin(); i!=a.end(); ++i) { cout&lt;&lt;*i; } } int main() { string a,b; cin&gt;&gt;a&gt;&gt;b; printhuge(mult(a,b)); return 0; } </code></pre> <p>All is working fine, but I need to use char[] instead of "string" . I know it's silly but I have to use that format necessary. So - how can I convert the code to work with char[] definition ?</p> <p>Any ideas is greatly appreciated, Thanks :)</p>
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    1. CODo you need to *produce* `char*` as the end result, or do you need to drop the use of strings altogether?
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    2. CODo you need to use `char*` as part of the assignment requirements? I can see no other reason to avoid using C++ strings.
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    3. COThe end result must be a char...
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