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    <p>A comment to your question on @PetrKozorezov 's answer. The shell is not behaving specially in any way. The shell worker process is just a normal process so if any process to which it is linked crashes then it will also crash. Another worker process will then be started. This is the normal <em>Erlang way</em>.</p> <p>Your <code>start/0</code> <strong>function</strong> just returns and does <strong>NOT</strong> terminate its process, it just outputs the "dying of boredom" message. That is why the loop keeps on going, it doesn't get an <code>exit</code> signal because no process has died.</p> <p>When you change the <code>start/0</code> function to end with <code>exit(normal)</code> <strong>then</strong> you do terminate the shell process so an <code>exit</code> signal is sent to the loop process which then gets the <code>{'EXIT',...,...}</code> message and dies.</p> <p>When @PetrKozorezov spawned your original <code>start/0</code> function in a separate process which then died after executing <code>start/0</code> it sent an exit <code>normal</code> signal to the loop process which caused it to die.</p> <p>This is perfectly normal Erlang behaviour and style. You would normally <strong>not</strong> end a <em>start</em> function with an <code>exit</code> but leave it up to the caller to decide when to die.</p> <p>One more small point: as the start function does a <code>spawn_link</code> you would normally call it <code>start_link</code> instead. A <code>start</code> function is assumed to just <code>spawn</code> a process. This is, of course, just a convention, but a common one, so you have not made an error.</p>
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