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    <blockquote> <p>How to get a Java Thread to notify itself?</p> </blockquote> <p>You can't get a Thread to notify itself since it is blocked in <code>wait()</code>. You <em>can</em> have another thread notify the thread by synchronizing on the same object that the thread is locking on and calling <code>notify()</code>. See the below code for a sample.</p> <p>That said, I'd recommend using a <code>BlockingQueue</code> to share data in this respect. It takes care of all of the locking and signaling. All the thread does is call <code>take()</code> and it will wait for the next operation to be added to the queue with a <code>put()</code>.</p> <p>Lastly, it's always recommended to implement <code>Runnable</code> instead of extending <code>Thread</code>. Once you turn your thread into a runnable you can use the <code>ExecutorService</code> classes as @Peter mentions in his answer. With an <code>ExecutorService</code> your code would look like:</p> <pre><code> public class OperationHandler implements Runnable { public void run() { // no looping or dequeuing needed // just execute the job } } // create a thread pool with a single thread worker ExecutorService threadPool = Executors.newSingleThreadExecutor(); // or create a thread pool with 10 workers // ExecutorService threadPool = Executors.newFixedThreadPool(10); // or you can create an open-ended thread pool // ExecutorService threadPool = Executors.newCachedThreadPool(); ... // do this once or many times threadPool.submit(new OperationHandler()); ... </code></pre> <p>But if you still want to tweak your code to get it to work:</p> <pre><code> private final Object lockObject = new Object(); public void run() { synchronized (lockObject) { ... lockObject.wait(); } } // called by another thread public void operationRequired() { synchronized (lockObject) { ... lockObject.notify(); } } </code></pre>
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    1. CO…and that is why you want a BlockingQueue, take() will block until the other thread offers some work. All of this is nicely wrapped in an ExecutorService.
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      1. USRalf H
    2. CO+1. Runnable will also allow you to work with ExecutorServices
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      1. USMel Nicholson
    3. CO+1 frankly the OP appears to be pointlessly reimplementing ExecutorService
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      1. USLouis Wasserman
 

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