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plurals
  1. POPHP value=arraykey + arraykey + arraykey
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    <p>I Have 3 Arrays</p> <p>Array 1 : </p> <pre><code> Array ( [0] =&gt; 0 [1] =&gt; 256 [2] =&gt; 512 [3] =&gt; 768 [4] =&gt; 1024 [5] =&gt; 1280 [6] =&gt; 1536 [7] =&gt; 1792 [8] =&gt; 2048 [9] =&gt; 2304 [10] =&gt; 2560 [11] =&gt; 2816 [12] =&gt; 3072 [13] =&gt; 3328 [14] =&gt; 3584 [15] =&gt; 3840 [16] =&gt; 4096 [17] =&gt; 4352 [18] =&gt; 4608 [19] =&gt; 4864 [20] =&gt; 5120 [21] =&gt; 5376 [22] =&gt; 5632 [23] =&gt; 5888 ) </code></pre> <p>Array 2 : </p> <pre><code>Array ( [0] =&gt; 0 [1] =&gt; 65536 [2] =&gt; 131072 [3] =&gt; 196608 [4] =&gt; 262144 [5] =&gt; 327680 [6] =&gt; 393216 [7] =&gt; 458752 [8] =&gt; 524288 [9] =&gt; 589824 [10] =&gt; 655360 [11] =&gt; 720896 [12] =&gt; 786432 [13] =&gt; 851968 [14] =&gt; 917504 [15] =&gt; 983040 [16] =&gt; 1048576 [17] =&gt; 1114112 [18] =&gt; 1179648 [19] =&gt; 1245184 [20] =&gt; 1310720 [21] =&gt; 1376256 [22] =&gt; 1441792 [23] =&gt; 1507328 [24] =&gt; 1572864 [25] =&gt; 1638400 [26] =&gt; 1703936 [27] =&gt; 1769472 [28] =&gt; 1835008 [29] =&gt; 1900544 [30] =&gt; 1966080 [31] =&gt; 2031616 ) </code></pre> <p>Array 3 : </p> <pre><code>Array ( [0] =&gt; 0 [1] =&gt; 1 [2] =&gt; 2 [3] =&gt; 3 [4] =&gt; 4 [5] =&gt; 5 [6] =&gt; 6 [7] =&gt; 7 [8] =&gt; 8 [9] =&gt; 9 [10] =&gt; 10 [11] =&gt; 11 [12] =&gt; 12 [13] =&gt; 13 [14] =&gt; 14 [15] =&gt; 15 [16] =&gt; 16 [17] =&gt; 17 [18] =&gt; 18 [19] =&gt; 19 [20] =&gt; 20 [21] =&gt; 21 [22] =&gt; 22 [23] =&gt; 23 [24] =&gt; 24 [25] =&gt; 25 [26] =&gt; 26 [27] =&gt; 27 [28] =&gt; 28 [29] =&gt; 29 [30] =&gt; 30 [31] =&gt; 31 ) </code></pre> <p>Given a number X which I know was calculated as <code>a1[i] + a2[j] + a3[k]</code> how can I calculate <code>i</code>, <code>j</code> and <code>k</code>?</p> <p>Examples:</p> <ol> <li>X = 458752 => <code>i=0</code>, <code>j=7</code>, <code>k=0</code> which is 458752 = 0 + 458752 + 0</li> <li>X = 131586 => <code>i=2</code>, <code>j=2</code>, <code>k=2</code> which is 131586 = 256 + 131072 + 2 </li> <li>X = 65793 => <code>i=1</code>, <code>j=1</code>, <code>k=1</code> which is 65793 = 256 + 65536 + 1</li> </ol>
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