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14451173
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2013-01-22T03:35:59.010
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2013-01-22T03:41:38.017
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2013-01-22T03:41:38.017
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text
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FYI: <a href="http://mathematica.stackexchange.com">http://mathematica.stackexchange.com</a> Make up some data: <pre><code>data = Table[{-1 - x^2 + y, 1 + x - y^2}, {x, -3, 3, 0.2}, {y, -3, 3, 0.2}]; </code></pre> Build a <code>ListStreamPlot</code> <pre><code>plot = ListStreamPlot[data, StreamStyle -> "Line", Frame -> False, PlotRangePadding -> 0] </code></pre> <img src="https://i.stack.imgur.com/vWLjn.png" alt="enter image description here"> In Mathematica everything is an expression - so even this plot is basically visualized code of graphics primitives. You can extract those primitives - including lines you need - by various ways. For example - just picking parts of expression you cam find all points comprising this plot: <pre><code>points = plot[[1, 2, 1]]; </code></pre> If you need to see the whole expression evaluate <code>plot//InputForm</code>. Now you could also do pattern matching to see inside expression. lets find all indexes comprising all your lines: <pre><code>indexes = Cases[plot, Line[index_] -> index, Infinity]; </code></pre> Now you have everything to analyse, draw and stylize your lines. For example - design an app that highlights a specific line in the original plot: <pre><code>Animate[Show[ plot, Graphics[{Red, Opacity[.5], , Thickness[.02], Line[points[[indexes[[k]]]]]}]] , {{k, 1, "lines"}, 1, Length[indexes], 1}, FrameMargins -> 0] </code></pre> <img src="https://i.stack.imgur.com/sRJfz.gif" alt="enter image description here">
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singulars
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1. This table or related slice is empty.
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1. POExtracting integral curves from discrete vector field (Mathematica)
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1. PTAnswer
UserLastEditorUserId
1. USVitaliy Kaurov
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1. USVitaliy Kaurov
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1. POExtracting integral curves from discrete vector field (Mathematica)
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1. VO
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2. VO
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3. VO
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1. COI believe I can make this work. Thanks for your help!
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 USueronica

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