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POAndroid - Set different OnTouch event on every child
 

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  1. POAndroid - Set different OnTouch event on every child
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    <p>Hello I'm trying to create a drag and drop view and I have succeed but I have one problem, I add my view dynamically like this</p> <pre><code>int k=0; for(int i=0;i&lt;badge_list_id.size()/2;i++) { Log.i(BaseID.TAG, "K : "+k); temp_badge_list_id.clear(); temp_badge_list_name.clear(); temp_badge_list_url.clear(); for(int j=k;j&lt;k+2;j++) { temp_badge_list_id.add(badge_list_id.get(j)); temp_badge_list_name.add(badge_list_name.get(j)); temp_badge_list_url.add(badge_list_url.get(j)); } llContainerBadgeList.addView(new ChildPopUpTopSend(context, temp_badge_list_id, temp_badge_list_name, temp_badge_list_url, badge_id, new callbackDragDrop())); k=k+2; } </code></pre> <p>and set the ontouch listener in the childview like this</p> <pre><code>private View.OnTouchListener mOnTouchDrag1=new View.OnTouchListener() { @Override public boolean onTouch(View v, MotionEvent event) { switch(event.getAction()) { case MotionEvent.ACTION_MOVE: { cbDrag.onDrag(badge_list_id.get(0), badge_id, BaseID.DRAGGING, event, v, badge_list_url.get(0)); break; }//inner case MOVE case MotionEvent.ACTION_UP: { cbDrag.onDrag(badge_list_id.get(0), badge_id, BaseID.STOP_DRAG, event, v, badge_list_url.get(0)); break; }//inner case UP case MotionEvent.ACTION_DOWN: { cbDrag.onDrag(badge_list_id.get(0), badge_id, BaseID.START_DRAG, event, v, badge_list_url.get(0)); break; }//inner case UP }//inner switch return true; } }; </code></pre> <p>and the cbDrag.onDrag function is like this</p> <pre><code>private class callbackDragDrop implements callbackDrag { @Override public void onDrag(int selected_badge, ArrayList&lt;Integer&gt; badge_id, int dragState, MotionEvent event, View v, String badge_url) { LinearLayout.LayoutParams par = (LinearLayout.LayoutParams) v.getLayoutParams(); switch(dragState) { case BaseID.START_DRAG: llContainerDrag = new LinearLayout(context); llContainerDrag.setLayoutParams(new LinearLayout.LayoutParams(LayoutParams.FILL_PARENT, (Util.getDisplayHeight(context)*8)/10)); ivDrag = new ImageView(context); imageLoader.DisplayImage(badge_url, ivDrag); par.topMargin = (int)event.getRawY() - (int)(v.getHeight()*1.5); par.leftMargin = (int)event.getRawX() - (int)(v.getWidth()*1.5); ivDrag.setLayoutParams(par); llContainerDrag.addView(ivDrag); PopUpTopSend.this.addView(llContainerDrag); break; case BaseID.DRAGGING: par.height = drag_height; par.width = drag_width; par.topMargin = (int)event.getRawY() - (int)(v.getHeight()*1.5); par.leftMargin = (int)event.getRawX() - (int)(v.getWidth()*1.5); ivDrag.setLayoutParams(par); break; case BaseID.STOP_DRAG: int drop_position = checkDropLocation(event); Log.i(BaseID.TAG, "Drop position : "+drop_position); ImageView ivDrop; switch(drop_position) { case 1: if(selected_badge!=badge_id.get(0)) { ivDrop = (ImageView) findViewById(R.id.ivBadgeSend1); imageLoader.DisplayImage(badge_url, ivDrop); PopUpTopSend.this.badge_id.remove(0); PopUpTopSend.this.badge_id.add(0, selected_badge); } break; case 2: if(selected_badge!=badge_id.get(1)) { ivDrop = (ImageView) findViewById(R.id.ivBadgeSend2); imageLoader.DisplayImage(badge_url, ivDrop); PopUpTopSend.this.badge_id.remove(1); PopUpTopSend.this.badge_id.add(1, selected_badge); } break; case 3: if(selected_badge!=badge_id.get(2)) { ivDrop = (ImageView) findViewById(R.id.ivBadgeSend3); imageLoader.DisplayImage(badge_url, ivDrop); PopUpTopSend.this.badge_id.remove(2); PopUpTopSend.this.badge_id.add(2, selected_badge); } break; } llContainerDrag.removeView(ivDrag); PopUpTopSend.this.removeView(llContainerDrag); break; } } } </code></pre> <p>let's say I have 8 view to added dynamically so my code will add 2 view every loop from 1 and 2 until 7 and 8 but what passed to the cbDrag.onDrag is always 7th and 8th data so when I'm trying to drag the image will be shown is the 7th and 8th image, where I go wrong? is it when I'm trying to set the ontouch listener the data will always be changed because I have it in the loop?is there any way to solve this?</p> <p>thank you</p>
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