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POHow do I print all the ways 4 different letters can combine in 2-letter pairs to fill four spots with each individual letter appearing exactly twice?
 

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  1. POHow do I print all the ways 4 different letters can combine in 2-letter pairs to fill four spots with each individual letter appearing exactly twice?
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    <p>What I have so far is this:</p> <pre><code>#include &lt;iostream&gt; #include &lt;algorithm&gt; using namespace std; int main(){ string genePool[16] = {"aa", "ab", "ac", "ad", "ba", "bb", "bc", "bd", "ca", "cb", "cc", "cd", "da", "db", "dc", "dd"}; string coco, code, deco, dede; int total = 0; for (int i = 0; i &lt; 16; i++){ coco = genePool[i]; for (int j = 0; j &lt; 15; j++){ code = genePool[j]; for (int k = 0; k &lt; 14; k++){ code = genePool[k]; for (int l = 0; l &lt; 13; l++){ code = genePool[l]; size_t a = count(coco.begin(), coco.end(), 'a') + count(code.begin(), code.end(), 'a') + count(deco.begin(), deco.end(), 'a') + count(dede.begin(), dede.end(), 'a'); size_t b = count(coco.begin(), coco.end(), 'b') + count(code.begin(), code.end(), 'b') + count(deco.begin(), deco.end(), 'b') + count(dede.begin(), dede.end(), 'b'); size_t c = count(coco.begin(), coco.end(), 'c') + count(code.begin(), code.end(), 'c') + count(deco.begin(), deco.end(), 'c') + count(dede.begin(), dede.end(), 'c'); size_t d = count(coco.begin(), coco.end(), 'd') + count(code.begin(), code.end(), 'd') + count(deco.begin(), deco.end(), 'd') + count(dede.begin(), dede.end(), 'd'); if (a = 2 || b = 2 || and c = 2 || d = 2){ total++; cout &lt;&lt; total &lt;&lt; ") "coco &lt;&lt; "," &lt;&lt; code &lt;&lt; "," &lt;&lt; deco &lt;&lt; "," &lt;&lt; dede &lt;&lt; endl; } } } } } return 0; } </code></pre> <p>It's been awhile since I've done anything with c++ and even then I wasn't too far in, so please excuse any offensively glaring errors. I will obligingly do better whenever better is pointed out :)</p>
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