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POHow .{n} and ?<option>: works in `Regexp` on Ruby 1.9.3 environment
 

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  1. POHow .{n} and ?<option>: works in `Regexp` on Ruby 1.9.3 environment
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    <p>I was trying to understand how <code>.{n}</code> and <code>?&lt;option&gt;:</code> works in <code>Regexp</code> on Ruby 1.9.3 environment. But couldn't understand how the below code produce the output:</p> <pre><code>irb(main):001:0&gt; %W{fin\n fi\n\n \n\n fin\r\n find}.grep /f.{2}(?m:.)\Z/ =&gt; ["fin\n", "fin\r\n", "find"] irb(main):002:0&gt; %W{fin\n fi\n\n \n\n fin\r\n find}.grep /f.{1}(?m:.)\Z/ =&gt; ["fin\n", "fi\n\n"] irb(main):003:0&gt; %W{fin\n fi\n\n \n\n fin\r\n find}.grep /f.{1}(?m:.)\Z/ =&gt; [] irb(main):010:0&gt; %W{fin\n fi\n\n \n\n fin\r\n find}.grep /f.(?m:.)\Z/ =&gt; ["fin\n", "fi\n\n"] irb(main):011:0&gt; %W{fin\n fi\n\n \n\n fin\r\n find}.grep /f.(m:.)\Z/ =&gt; [] irb(main):012:0&gt; %W{fin\n fi\n\n \n\n fin\r\n find}.grep /f.(?m:.)\z/ =&gt; [] </code></pre> <p>Can anyone help me to understand how the above code worked to generate the mentioned output in <code>IRB</code> terminal?</p> <p>Thanks,</p> <hr> <p><strong><em>As per @Kevin last paragraph</em></strong> I tried below and found expected and desirable output :</p> <pre><code>irb(main):014:0&gt; %W{fin fi\n\n \n\n fin\r\n find}.grep /f.(?m:.)\z/ =&gt; ["fin"] irb(main):015:0&gt; %W{fin fi\n\n \n\n fin\r find}.grep /f.(?m:.)\z/ =&gt; ["fin"] irb(main):016:0&gt; %W{fin fi\n \n\n fin\r\n find}.grep /f.(?m:.)\z/ =&gt; ["fin", "fi\n"] irb(main):017:0&gt; %W{fin fi\n \n\n fr\n find}.grep /f.(?m:.)\z/ =&gt; ["fin", "fi\n", "fr\n"] irb(main):018:0&gt; </code></pre> <p>Thank you very much <strong><em>@Kevin</em></strong> . You helped me to understand the whole concept!</p>
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    1. CO`m` option in Ruby is actually DOTALL option, which allow `.` to match `\n`. (Not sure why Ruby differs on this point, though).
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    2. CODon't you mean `.{n}` instead of `.(n)` (with `n` any number)?
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    3. CO@Tinctorius Sorry! I corrected now.
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