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14385294
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2013-01-17T18:02:19.117
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2017-08-09T14:53:00.343
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2017-08-09T14:53:00.343
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using a UDF makes the most sense it's flexible for all projects, the one I generally use is at my blog, <a href="http://sqlthis.blogspot.com/2005/02/list-to-table.html" rel="nofollow noreferrer">http://sqlthis.blogspot.com/2005/02/list-to-table.html</a> because it's written to take your input string and a delimiter, it can be any single character for a delimiter. I wrote the one at the link above, but then afterwards I found many sites publishing a similar solution, so parts may have been inspired from forums that I am a member of... it works, and hopefully it will work for you as well. edit 2017-08-09 as suggested, I've cloned the code block below. thanks! <pre><code>CREATE FUNCTION udfListToTable (@HList VarChar(2000), @Delimiter CHAR(1)) RETURNS @ListTable TABLE (Field1 VARCHAR(6)) AS BEGIN --By: Francisco Tapia --Date: 2/1/2005 --Purpose: To convert a Comma delimited text to a Temp Variable table To help avoid dynamic sql -- Instead you can join the temp table or use it in your where clause if a field is IN the subquery DECLARE @FieldText as VarChar(6) IF RIGHT(RTRIM(@HLIST),1) <>@Delimiter SET @HList = @HList + @Delimiter WHILE CHARINDEX(@Delimiter, @HList) > 0 BEGIN IF CHARINDEX(@Delimiter, @HList) > 0 BEGIN SELECT @FieldText =LEFT(@HList, CHARINDEX(@Delimiter, @HList)-1) END ELSE BEGIN SELECT @FieldText = RTRIM(LTRIM(@HList)) END --Insert into Variable Table INSERT INTO @ListTable(Field1) SELECT RTRIM(LTRIM(@FieldText)) --Remove Item from list SELECT @HList = RIGHT(RTRIM(@HList), LEN(RTRIM(@HList)) - CHARINDEX(@Delimiter, @HList)) END RETURN END </code></pre>
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1. POHow Do I Split a Delimited String in SQL Server Without Creating a Function?
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1. PTAnswer
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1. USSeeCoolGuy
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1. USSeeCoolGuy
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