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POPython Zipfile - Invalid Argument Errno 22
 

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  1. POPython Zipfile - Invalid Argument Errno 22
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    <p>I have a .zip file and would like to know the names of the files within it. Here's the code:</p> <pre><code>zip_path = glob.glob(path + '/*.zip')[0] file = open(zip_path, 'r') # opens without error if zipfile.is_zipfile(file): print str(file) # prints to console my_zipfile = zipfile.ZipFile(zip_path) # throws IOError </code></pre> <p>Here is the traceback:</p> <pre><code>&lt;open file u'/Users/me/Documents/project/uploads/assets/peter/offline_message/offline_imgs.zip', mode 'r' at 0x107b2a150&gt; Traceback (most recent call last): File "/Users/me/Documents/project/admin_dev/proj_name/views.py", line 1680, in get_dps_app_builder_assets link_to_assets_zip = zip_dps_app_builder_assets(server_url, app_slug, button_slugs) File "/Users/me/Documents/project/admin_dev/proj_name/views.py", line 1724, in zip_dps_app_builder_assets my_zipfile = zipfile.ZipFile(zip_path) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/zipfile.py", line 712, in __init__ self._GetContents() File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/zipfile.py", line 746, in _GetContents self._RealGetContents() File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/zipfile.py", line 779, in _RealGetContents fp.seek(self.start_dir, 0) IOError: [Errno 22] Invalid argument </code></pre> <p>I am very confused as to why this is happening since the file is clearly there and is a valid .zip file. The documentation clearly states that you can pass it either the path to the file or a file-like object, neither of which work in my case:</p> <p><a href="http://docs.python.org/2/library/zipfile#zipfile-objects" rel="nofollow">http://docs.python.org/2/library/zipfile#zipfile-objects</a></p>
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    1. CO`file` is a built-in. Try not to use as a variable name.
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      1. POPython Zipfile - Invalid Argument Errno 22
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    2. COI don't actually use that as the variable name, I just changed it to make things as simple as possible. Thanks, though.
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      1. POPython Zipfile - Invalid Argument Errno 22
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    3. COThe `is_zipfile()` function just checks for a magic number and might be fooled. It looks to me like `zipfile` is attempting to seek to somewhere before the start of the file, which would typically be due to an invalid zip file. Are you sure the same file works with the conventional zip utility?
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