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14349498
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2013-01-16T00:26:48.930
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2013-01-16T01:36:54.030
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Decorators are actually just a shortcut to something you can do manually. This code: <pre><code>@deco def myfunc(): print(" myfunc() called.") </code></pre> Is equivalent to: <pre><code>def myfunc(): print(" myfunc() called.") myfunc = deco(myfunc) </code></pre> For the sake of discussing this, let's say the original were still available as <code>original_myfunc</code> (even though in reality it isn't). So, when you do this: <pre><code>deco(myfunc)() </code></pre> What you end up calling is: <pre><code>deco(deco(original_myfunc))() </code></pre> And if you trace through that, it should be obvious why it prints what you expected. But let's do the exercise anyway. First, you call <code>deco(original_myfunc)</code>, and it does this: <pre><code>def kdeco(): print("before myfunc() called.") original_myfunc() print(" after myfunc() called.") </code></pre> return kdeco So that returns a function that prints the "before", calls <code>original_myfunc</code>, then prints the "after". And now we pass <code>deco(original_myfunc)</code> to <code>deco</code> again, which does this: <pre><code>def kdeco(): print("before myfunc() called.") deco(original_myfunc)() print(" after myfunc() called.") return kdeco </code></pre> So, that returns a function that prints the "before", then calls <code>deco(original_myfunc)</code>—which itself prints the "before", calls <code>original_myfunc</code>, and prints "after"—then prints "after". That's why you get the output you do.
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