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    <p>If you are generating the IL yourself then it is possible. What typeof(T) does is hardcode the runtime type handle with ldtoken instruction and then calls Type.GetTypeFromHandle. When I generate IL I generate equivelent all the time. Here is some utility method from some code I wrote </p> <pre><code>/// &lt;summary&gt; /// Pushes the specified member onto the evaluation stack. /// &lt;/summary&gt; /// &lt;param name="generator"&gt;The generator.&lt;/param&gt; /// &lt;param name="member"&gt;The member.&lt;/param&gt; public static void EmitLoadMemberInfo(this ILGenerator generator, MemberInfo member) { switch (member.MemberType) { case MemberTypes.Method: generator.Emit(OpCodes.Ldtoken, member as MethodInfo); generator.Emit(OpCodes.Call, typeof(MethodBase).GetMethod("GetMethodFromHandle", BindingFlags.Public | BindingFlags.Static, null, new[] { typeof(RuntimeMethodHandle) }, null)); break; case MemberTypes.TypeInfo: generator.Emit(OpCodes.Ldtoken, member as Type); generator.Emit(OpCodes.Call, typeof(Type).GetMethod("GetTypeFromHandle", BindingFlags.Public | BindingFlags.Static)); break; case MemberTypes.Field: generator.Emit(OpCodes.Ldtoken, member as FieldInfo); generator.Emit(OpCodes.Call, typeof(FieldInfo).GetMethod("GetFieldFromHandle", BindingFlags.Public | BindingFlags.Static)); break; case MemberTypes.Constructor: generator.Emit(OpCodes.Ldtoken, member as ConstructorInfo); generator.Emit(OpCodes.Call, typeof(MethodBase).GetMethod("GetMethodFromHandle", BindingFlags.Public | BindingFlags.Static, null, new[] { typeof(RuntimeMethodHandle) }, null)); break; default: throw new NotSupportedException("Unsupported token type."); } } </code></pre> <p>I should also mention there are some mocking frameworks that kinda support that. I put an example an another post due to size</p>
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