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When you say "only one set of animation is run" I'm assuming that means <code>greenCircleAppear</code> and <code>redCircleAppear</code> begin the sequence of images appearing and the user pressing a button. If that's the case, I'd recommend not using a <code>for</code> loop in <code>viewDidAppear</code> but instead have <code>viewDidAppear</code> initialize the current state and call a method that presents the next animation. When the animation is finished, have it call the method that presents the next animation. Something along these lines: Add this to the interface: <pre><code>@interface ViewController () @property NSInteger currentIteration; @end </code></pre> This is in the implementation: <pre><code>- (void)viewDidAppear:(BOOL)animated { self.currentIteration = 0; [self showNextAnimation]; } - (void)greenCircleAppear:(id)arg1 finished:(id)arg2 context:(id)arg3 { //perform animation NSLog(@"green"); [self showNextAnimation]; } - (void)redCircleAppear:(id)arg1 finished:(id)arg2 context:(id)arg3 { //perform animation NSLog(@"red"); [self showNextAnimation]; } - (void)showNextAnimation { self.currentIteration = self.currentIteration + 1; if (self.currentIteration <= 20) { //you should replace '20' with a constant int r = arc4random() % 2; NSLog(@"%i", r); if(r==1) { [self greenCircleAppear:nil finished:nil context: nil]; } else { [self redCircleAppear:nil finished:nil context: nil]; } } else { //do what needs to be done after the last animation } } </code></pre>
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1. POGetting two images to appear in random sequence iOS
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1. POGetting two images to appear in random sequence iOS
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1. COHey @SSteve, this is a great way to implement it. Thank you so much for your input!
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