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    <p>Order of operations, as presented:</p> <ol> <li><code>a</code> is globally initialized on startup. to 7</li> <li>Initializer of for-loop is hit first, <code>test()</code> decrements <code>a</code> to 6, then returns the prior value (7), which is ignored. </li> <li>The test case of for-loop is hit, <code>test()</code> decrements <code>a</code> to 5, then returns the prior value (6) which passes the non-zero test so the for-loop can continue.</li> <li>The <code>cout</code> statement; <code>test()</code> decrements <code>a</code> to 4, returning the prior value <strong>(5)</strong> which is sent to <code>cout</code>.</li> <li>The increment-statement of the for-loop is executed. <code>test()</code> decrements <code>a</code> to 3, returning the prior value (4), which is ignored.</li> <li>The test case of the for-loop is hit. <code>test()</code> decrements <code>a</code> to 2, returning the prior value (3), which passes the non-zero test and the loop continues.</li> <li>The <code>cout</code> statement; <code>test()</code> decrements <code>a</code> to 1, returning the prior value <strong>(2)</strong> which is sent to <code>cout</code>.</li> <li>The increment-statement of the for-loop is executed. <code>test()</code> decrements <code>a</code> to 0, returning the prior value (1), which is ignored.</li> <li>The test case of the for-loop is hit. <code>test()</code> decrements <code>a</code> to -1, returning the prior value (0), which fails the non-zero test and the loop terminates.</li> </ol> <p>Now. Start that loop at 6 or 8 and see what happens. =P</p>
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    1. POHow does this for-loop actually work?
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    1. USWhozCraig
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    1. POHow does this for-loop actually work?
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    1. COthanks, but why it returns the prior value? is there a rule or something about the static variables?
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      1. USddacot
    2. CO@ddacot The post-unary operators (both -- and ++) work that way by design. The statement `x = a++` does two things. (1) increments `a` by one, and (2) returns the *prior* value of `a` as the expression value, which is then assigned to `x`. For some reason instructors teach this completely wrong. They say "`a` is assigned to `x`, then `a` is incremented." While it may *appear* that way, that is not, in fact, the correct order of operations.
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    3. COthanks, now i really got it.
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      1. USddacot
 

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