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POHow to obtain the scale and rotation angle from LogPolar transform
 

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  1. POHow to obtain the scale and rotation angle from LogPolar transform
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    <p>I'm trying to use LogPolar transform to obtain the scale and the rotation angle from two images. Below are two 300x300 sample images. The first rectangle is 100x100, and the second rectangle is 150x150, rotated by 45 degree. </p> <p><img src="https://i.stack.imgur.com/i5Es6.png" alt="enter image description here"> <img src="https://i.stack.imgur.com/w3Kmx.png" alt="enter image description here"></p> <p>The algorithm:</p> <ol> <li>Convert both images to LogPolar.</li> <li>Find the translational shift using Phase Correlation.</li> <li>Convert the translational shift to scale and rotation angle (how to do this?).</li> </ol> <p>My code:</p> <pre><code>#include &lt;opencv2/imgproc/imgproc.hpp&gt; #include &lt;opencv2/imgproc/imgproc_c.h&gt; #include &lt;opencv2/highgui/highgui.hpp&gt; #include &lt;iostream&gt; int main() { cv::Mat a = cv::imread("rect1.png", 0); cv::Mat b = cv::imread("rect2.png", 0); if (a.empty() || b.empty()) return -1; cv::imshow("a", a); cv::imshow("b", b); cv::Mat pa = cv::Mat::zeros(a.size(), CV_8UC1); cv::Mat pb = cv::Mat::zeros(b.size(), CV_8UC1); IplImage ipl_a = a, ipl_pa = pa; IplImage ipl_b = b, ipl_pb = pb; cvLogPolar(&amp;ipl_a, &amp;ipl_pa, cvPoint2D32f(a.cols &gt;&gt; 1, a.rows &gt;&gt; 1), 40); cvLogPolar(&amp;ipl_b, &amp;ipl_pb, cvPoint2D32f(b.cols &gt;&gt; 1, b.rows &gt;&gt; 1), 40); cv::imshow("logpolar a", pa); cv::imshow("logpolar b", pb); cv::Mat pa_64f, pb_64f; pa.convertTo(pa_64f, CV_64F); pb.convertTo(pb_64f, CV_64F); cv::Point2d pt = cv::phaseCorrelate(pa_64f, pb_64f); std::cout &lt;&lt; "Shift = " &lt;&lt; pt &lt;&lt; "Rotation = " &lt;&lt; cv::format("%.2f", pt.y*180/(a.cols &gt;&gt; 1)) &lt;&lt; std::endl; cv::waitKey(0); return 0; } </code></pre> <p>The log polar images:</p> <p><img src="https://i.stack.imgur.com/WNgUH.png" alt="enter image description here"> <img src="https://i.stack.imgur.com/cScXx.png" alt="enter image description here"></p> <p>For the sample image images above, the translational shift is <code>(16.2986, 36.9105)</code>. I have successfully obtain the rotation angle, which is <code>44.29</code>. But I have difficulty in calculating the scale. How to convert the given translational shift to obtain the scale?</p>
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    1. COHI, Can you go through the paper" ROBUST IMAGE REGISTRATION USING LOG-POLAR TRANSFORM by George Wolberg"... i Think it is very simple and clear on how to recover scale and rotation in Log-Polar Space....
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    2. CO@G453 I've read the paper and also some others. I don't know if the explanations in the papers are unclear or its me that so stupid but I still cannot write the proper code for recovering the scale.
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    3. COThe shift vector has 2 coordinates, one is the angle and the other is the log of the scale.
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