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POHow can I draw a "soft" line in WPF (presumably using a LinearGradientBrush)?
 

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  1. POHow can I draw a "soft" line in WPF (presumably using a LinearGradientBrush)?
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    <p>I'm trying to draw a line with soft edges, regardless of the slope. </p> <p>Here's the code I have so far: </p> <pre><code>&lt;Line HorizontalAlignment="Stretch" VerticalAlignment="Center" Stretch="Uniform" StrokeThickness="5" X1="0" Y1="0" X2="1" Y2="0"&gt; &lt;Shape.Stroke&gt; &lt;LinearGradientBrush StartPoint="0,0" EndPoint="0,1"&gt; &lt;GradientStop Color="Transparent" Offset="0" /&gt; &lt;GradientStop Color="Green" Offset="0.5" /&gt; &lt;GradientStop Color="Transparent" Offset="1" /&gt; &lt;/LinearGradientBrush&gt; &lt;/Shape.Stroke&gt; &lt;/Line&gt; </code></pre> <p>This makes sense to me, since the line is horizontal, and the linear gradient is vertical, with the edges being transparent and the middle of the line being solid green. </p> <p>The result is pleasing:<br> <a href="http://img15.imageshack.us/img15/4108/horizontalsoftline.png">http://img15.imageshack.us/img15/4108/horizontalsoftline.png</a><br> Zoomed in so you can see the gradient:<br> <a href="http://img225.imageshack.us/img225/5027/horizontalsoftlinezoomeb.png">http://img225.imageshack.us/img225/5027/horizontalsoftlinezoomeb.png</a> </p> <p>However, when the line is no longer horizontal, the gradient is calculated based on the line's bounding rectangle, rather than on the geometry of the line itself. The result is a slanted line that is shaded vertically, instead of the gradient being perpendicular to the line:<br> <a href="http://img183.imageshack.us/img183/7250/slantedsoftline.png">http://img183.imageshack.us/img183/7250/slantedsoftline.png</a> </p> <p>Does anyone know how WPF handles soft edges? I can't find anything on Google or MSDN, and I know there is a way to do this somewhow...</p>
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    1. COGood question. I've been trying to figure out how to make borders with lines like that. I have a feeling the answers will be related.
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      1. USBryan Anderson
 

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