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    <p>The easy answer is: don't print within the <code>while</code> loop, but concatenate up a string to print at the end:</p> <pre><code>result = '' while z &lt; y+1: a = x[z-1] result += str(test[a]) z = z + 1 print result </code></pre> <p>If there are going to be a whole bunch of things, instead of concatenating strings on the fly, use a <code>list</code> and <code>join</code> at the end:</p> <pre><code>result = [] while z &lt; y+1: a = x[z-1] result.append(str(test[a])) z = z + 1 print ''.join(result) </code></pre> <p>But you say you want to get an integer. Do you need that integer, for any reason other than to print it out? If so, you <em>could</em> build up a string and then convert it to an integer:</p> <pre><code>result = [] while z &lt; y+1: a = x[z-1] result.append(str(test[a])) z = z + 1 val = int(''.join(result)) </code></pre> <p>But this is silly. Why not just build up the value as an integer in the first place?</p> <pre><code>val = 0 while z &lt; y+1: a = x[z-1] val = val * 10 + test[a] z = z + 1 </code></pre> <p>Since you seem to be using Python 2, the only way to print without adding a newline, instead adds a space, which doesn't help. But Python 3—and Python 2 with <code>from __future__ import print_function</code>—has a more flexible alternative:</p> <pre><code>while z &lt; y+1: a = x[z-1] print(test[a], end='') z = z + 1 print() </code></pre> <p>Or you can <code>write</code> directly to <code>stdout</code>:</p> <pre><code>while z &lt; y+1: a = x[z-1] sys.stdout.write(str(test[a])) z = z + 1 sys.stdout.write('\n') </code></pre>
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    1. POHow do I make a 'while' loop print the results of the loop's conditional into a single line(concatenated)?
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    1. COI get an error. TypeError: cannot concatenate 'str' and 'int' objects. I think this is because result = a blank string, and test[a] is an integer
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    2. CO@01110100: Yes, if `test[a]` is an integer… let me adjust the answer.
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