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POBackbone.js - How do load list or individual items from JSON on different routes?
 

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  1. POBackbone.js - How do load list or individual items from JSON on different routes?
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    <p>I have just started working with Backbone.js by creating a simple portfolio site for myself. There is not much functionality at the moment but I hope to add more &amp; more as I become familiar with the library. I am using json to populate the data for the site which either lists all my portfolio items or displays one of them depending on the route. I have the list of portfolio items working/showing but am struggling to just show one item for a specific route (/#projects/2 for example), this is where I need help.</p> <p>I have tried to keep everything as simple as possible while I start learning Backbone &amp; have seen the various Boilerplates &amp; tutorials, none of which helped me hugely. </p> <p>At these routes, I would like this to happen:</p> <ol> <li>/ - list of portfolio items</li> <li>/#projects - list of portfolio items</li> <li>/#projects/3 - one portfolio item</li> </ol> <p>I have put my attempt into JSbin but it is not working because I don't know how to load the json properly...</p> <ul> <li><a href="http://jsbin.com/asezul/6/edit" rel="nofollow">http://jsbin.com/asezul/6/edit</a> to edit</li> <li><a href="http://jsbin.com/asezul/6/" rel="nofollow">http://jsbin.com/asezul/6/</a> to view</li> </ul> <p>I am certain my problem arises because I am loading all items into the collection rather than the model. Is that right?</p> <ol> <li><strong>How can I make this work?</strong></li> <li><strong>How can I improve this?</strong></li> </ol> <p><strong>[EDIT --------------------]</strong></p> <p><strong>After Peter's very kind help below, I am still in need of assistance. He said:</strong></p> <blockquote> <p>A view displays 1 model, a collection view displays a list of views, one per model.</p> </blockquote> <p><strong>So, how do I create a View to display one item from the json data &amp; then create the collection view to display all of them? The reason I ask is because I can return all them without much of a problem but returning a single item is proving quite tricky..</strong></p> <p><strong>I updated my code example too: <a href="http://jsbin.com/asezul/8/edit" rel="nofollow">http://jsbin.com/asezul/8/edit</a></strong></p> <p><strong>[---------------------EDIT]</strong></p> <p> </p> <p>Please let me know if you need more information, I am new to Backbone &amp; may have missed an important part that would help to answer my questions.</p> <p>Here's some code excerpts but I suggest viewing the code in JSbin:</p> <p><strong>The model:</strong></p> <pre><code>SITE.Project = Backbone.Model.extend({ initialize: function() { console.log(this, this.attributes.name); } }); </code></pre> <p><strong>The collection:</strong></p> <pre><code>SITE.Projects = Backbone.Collection.extend({ model: SITE.Project, url: 'content.json', parse: function(response) { console.log(response); return response.portfolio; } }); </code></pre> <p><strong>A view:</strong></p> <pre><code>SITE.ProjectsView = Backbone.View.extend({ el: '#main', initialize: function() { _.bindAll(this, 'render'); // create a collection this.collection = new SITE.Projects(); // Fetch the collection and call render() method var that = this; this.collection.fetch({ success: function () { that.render(); } }); }, template: SITE.helpers.template('project-list'), render: function() { $(this.el).html(this.template({ projects: this.collection.toJSON() })); } }); </code></pre> <p><strong>The router:</strong></p> <pre><code>SITE.Router = Backbone.Router.extend({ initialize: function() { this.el = $('#main'); }, routes: { "": "index", "projects": "projects", "projects/:id": "project" }, // Homepage / List of projects index: function() { var view = new SITE.ProjectsView(); }, // List of projects projects: function() { var view = new SITE.ProjectsView(); }, // Individual Project project: function(id) { var view = new SITE.ProjectView(); console.log("You are trying to reach project " + id); } }); </code></pre>
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