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PO
primarykey
Id
14095521
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
0
CommunityOwnedDate
CreationDate
2012-12-30T22:51:23.653
FavoriteCount
0
LastActivityDate
2012-12-31T06:26:20.607
LastEditDate
2012-12-31T06:26:20.607
LastEditorUserId
338913
OwnerUserId
592323
ParentId
14095450
PostTypeId
2
Score
9
ViewCount
0
LastEditorDisplayName
text
Body
While solving the compiler error simply requires the <code>operator()</code> to be public as according to most other answers to this question, you should note that your comparator isn't a valid strict comparator. A strict comparator has to return <code>false</code> for elements which are treated as being equal. You should also use const references instead of values for the parameter types of your comparator. I want to present you multiple options to solve your problem (not the compiler-error but the original problem, sorting a string in reversed lexical order). All of them return <code>false</code> for two equal elements. The first option is your solution but I fixed the strictness: <pre><code>template <typename T> class ReverseComparator{ public: bool operator()(const T& l, const T& r){return (r < l);} }; std::sort(str.begin(), str.end(), ReverseComparator()); </code></pre> The second option uses C++11's lambda function, but is essentially the same: <pre><code>std::sort(str.begin(), str.end(), [](const T& l, const T& r){return (r < l);}); </code></pre> As a third option, as first proposed by Mooning Duck, you could simply use the std functor for <code>operator></code> on your type <code>char</code>: <pre><code>std::sort(str.begin(), str.end(), std::greater<char>()); </code></pre> The fourth option (the simplest one) would be to use the default comparator on the reversed string, as first proposed by Peter Wood (note the <code>r</code>!): <pre><code>std::sort(str.rbegin(), str.rend()); </code></pre>
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1. POC++ Reversely sort characters in a string
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