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    <p>we can do this with a couple of analytics:</p> <pre><code>SQL&gt; alter session set nls_date_format='yy/mm/dd'; Session altered. SQL&gt; select id, min(val) date_from, max(val) date_till 2 from (select id, val, max(grp) over(partition by id order by val) grp 3 from (select id, val, lag(val, 1) over(partition by id order by val), 4 case 5 when lag(val, 1) over(partition by id order by val) &lt; val - 1 then 6 row_number() over(partition by id order by val) 7 when row_number() over(partition by id order by val) = 1 then 8 1 9 end grp 10 from mytab)) 11 group by id, grp 12 order by id, date_from 13 / ID DATE_FRO DATE_TIL ---------- -------- -------- 9465 12/12/20 12/12/22 9465 12/12/25 12/12/26 9466 12/12/21 12/12/25 9466 12/12/27 12/12/27 </code></pre> <p>i.e. first we break the result set into groups where a group is defined as contigious dates for a given ID. We do this by checking the prior date and seeing if its &lt; the current rows date - 1 with <code>lag(val, 1) over(partition by id order by val)</code></p> <pre><code>SQL&gt; select id, val, lag(val, 1) over(partition by id order by val), 2 case 3 when lag(val, 1) over(partition by id order by val) &lt; val - 1 then 4 row_number() over(partition by id order by val) 5 when row_number() over(partition by id order by val) = 1 then 6 1 7 end grp 8 from mytab 9 / ID VAL LAG(VAL, GRP ---------- -------- -------- ---------- 9465 12/12/20 1 9465 12/12/21 12/12/20 9465 12/12/22 12/12/21 9465 12/12/25 12/12/22 4 9465 12/12/26 12/12/25 9466 12/12/21 1 9466 12/12/22 12/12/21 9466 12/12/23 12/12/22 9466 12/12/24 12/12/23 9466 12/12/25 12/12/24 9466 12/12/27 12/12/25 6 11 rows selected. </code></pre> <p>we need to fill in the blanks next so that the blanks associate the non-null group that preceeded it. i.e. we apply a max() to this with <code>max(grp) over(partition by id order by val)</code> the order by here means that we are only taking the max row seen up to that point and not the max across the whole set. </p> <pre><code>SQL&gt; select id, val, max(grp) over(partition by id order by val) grp 2 from (select id, val, lag(val, 1) over(partition by id order by val), 3 case 4 when lag(val, 1) over(partition by id order by val) &lt; val - 1 then 5 row_number() over(partition by id order by val) 6 when row_number() over(partition by id order by val) = 1 then 7 1 8 end grp 9 from mytab) 10 / ID VAL GRP ---------- -------- ---------- 9465 12/12/20 1 9465 12/12/21 1 9465 12/12/22 1 9465 12/12/25 4 9465 12/12/26 4 9466 12/12/21 1 9466 12/12/22 1 9466 12/12/23 1 9466 12/12/24 1 9466 12/12/25 1 9466 12/12/27 6 11 rows selected. </code></pre> <p>now its a simple group by (id, grp) to be applied, taking the min() and max() for each id+group.</p>
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