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    <p>C89/90 still has the implicit int rule, so <code>main()</code> is equivalent to <code>int main()</code>. By leaving off the return type, you've implicitly defined the return type as <code>int</code>. Some may consider this sloppy, but it's strictly conforming (i.e., involves no implementation defined, undefined or unspecified behavior).</p> <p>For C99, the implicit <code>int</code> rule has been removed, so <code>main()</code> isn't defined. <em>However</em>, a compiler is only required to "issue a diagnostic" upon encountering a violation of a <code>Shall</code> or <code>Shall not</code> clause -- it's still free to continue compiling after issuing the diagnostic. Exactly what constitutes a diagnostic is implementation defined. As such, all that's needed for gcc to conform in this respect is documentation to say that the warning it issues is to be considered a diagnostic.</p> <p>Edit: "implicit <code>int</code>" in the C89/90 standard isn't really a single rule in a single place -- it's spread around in a couple of places. The primary one is §6.5.2.1, where it says:</p> <blockquote> <p>-- <code>int</code>, <code>signed</code>, <code>signed int</code>, or no type specifiers</p> </blockquote> <p>This is part of a list, where all the items on each line of the list are considered equivalent, so this is saying that (unless otherwise prohibited) lack of a type specifier is equivalent to specifying (signed) <code>int</code>.</p> <p>For function parameters, there's a separate specification (at §6.7.1) that: "Any parameter that is not declared has type <code>int</code>."</p>
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    1. POWhat if I omit the return type of main function in C?
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    1. CO[C89/90 still has the implicit int rule] Could you give me the citation in Standard please?
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    2. CO@larmbr: See edited answer [I hate standards printed on paper].
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