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POWhy does my JQuery script add html tags when appending it?
 

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  1. POWhy does my JQuery script add html tags when appending it?
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    <p>I have a problem when sending a json array to my jquery script where I want to append it to a div. In php I created a json array containing the following html code:</p> <pre><code>&lt;li id="1234"&gt; &lt;span class="some"&gt;$1&lt;/span&gt; &lt;span class="some2"&gt;$1&lt;/span&gt; &lt;div class="somediv"&gt;&lt;/div&gt; &lt;/li&gt; </code></pre> <p>So the whole json array looks like this:</p> <pre><code>[{"id":"12435","text":"&lt;li id=\"1234\"&gt;&lt;span class=\"some\"&gt;$1&lt;/span&gt;"},{"id":"13542","text":"&lt;span class=\"some2\"&gt;$1&lt;/span&gt;&lt;div class=\"somediv\"&gt;&lt;/div&gt;&lt;/li&gt;"}]; </code></pre> <p>Now I used getJSON to get the json object and then I append the result to a div like this: <code>$(".container").append(val);</code></p> <p>Now the problem is that somehow when trying to append the JSON results, this is what is beeing appended:</p> <pre><code>&lt;li id="1234"&gt; &lt;span class="some"&gt;$1&lt;/span&gt; &lt;/li&gt; &lt;li id="1234"&gt; &lt;span class="some2"&gt;$1&lt;/span&gt; &lt;div class="somediv"&gt;&lt;/div&gt; &lt;/li&gt; </code></pre> <p>When I try to output my <code>val</code> with <code>alert(val)</code> it clearly shows that the json result is correct (without the closing <code>&lt;li&gt;</code> tag), but when appending it, the <code>&lt;li&gt;</code> tag is added.</p> <p>Does anyone have any idea what could be the reason for this?</p> <p>This is how I get the values from my php file:</p> <pre><code>$.getJSON("../ajax.php?action=getresults", function(data) { var obj = $.parseJSON(data); $.each(obj, function(key,val) { $.each(obj[key], function(key, dval) { if(key == "text") { alert(dval); $(".container").append(dval); } }) }); }); </code></pre>
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    1. COShow us how you're getting the values, assuming you did'nt just append the JSON string "as is" to the page?
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    2. CO`.append()` *requires* valid HTML, not just fragments.
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    3. COYou're using `$.getJSON`, you don't need the `$.parseJSON`.
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      1. USRocket Hazmat
 

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