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POGetting an appropriate array using MySQL for PHP
 

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  1. POGetting an appropriate array using MySQL for PHP
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    <p>I have to show a listing of products for a store.All I have is a store id and I have to associate 6 tables to get so. Query I have used is fetching me the records correctly but not in the desirable array format. I don't know if the array format I want is possible or not. My SQL is as follows:</p> <pre><code>SELECT DISTINCT KR.knifename,KR.id,CAT.categoryname,KR.knifecode FROM assocknives AS AK INNER JOIN kniferegisters AS KR ON KR.id = AK.kniferegister_id INNER JOIN categories AS CAT ON CAT.id = KR.sub_category_id INNER JOIN stores AS STR ON STR.id = AK.store_id INNER JOIN brands AS BRND ON BRND.id = AK.brand_id INNER JOIN assocknifeprices AS AKP ON AKP.assocknife_id = AK.id WHERE AK.store_id='.$storeId.' AND BRND.is_active ="1" AND STR.is_active ="1" </code></pre> <p>Which gives me the array as</p> <pre><code>Array ( [0] =&gt; Array ( [KR] =&gt; Array ( [knifename] =&gt; xxx [id] =&gt; xxx [knifecode] =&gt; xxx ) [CAT] =&gt; Array ( [categoryname] =&gt; xxx ) ) [1] =&gt; Array ( [KR] =&gt; Array ( [knifename] =&gt; xxx [id] =&gt; xxx [knifecode] =&gt; xxx ) [CAT] =&gt; Array ( [categoryname] =&gt; xxx ) ) ) </code></pre> <p>The result is correct but I want to get it as</p> <pre><code>Array ( [categoryname1] =&gt; Array ( [0] =&gt; Array ( [knifename] =&gt; xxx [id] =&gt; xxx [knifecode] =&gt; xxx ) [1] =&gt; Array ( [knifename] =&gt; xxx [id] =&gt; xxx [knifecode] =&gt; xxx ) ) [categoryname2] =&gt; Array ( [0] =&gt; Array ( [knifename] =&gt; xxx [id] =&gt; xxx [knifecode] =&gt; xxx ) [1] =&gt; Array ( [knifename] =&gt; xxx [id] =&gt; xxx [knifecode] =&gt; xxx ) ) </code></pre> <p>) I am sorry If this seems to be a silly thing but this array format will really help my cause. Thanks all for your attention.</p>
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    1. USMark Davidson
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    1. CORemove the `AS AK`s after the table declaration. If you want to name your tables without getting the handlers back in the results, just remove the `AS` and your query will remain functional.
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      1. USSébastien Renauld
    2. CO[What have you tried?](http://www.whathaveyoutried.com)
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      1. USAleks G
    3. COWell, the data is certainly not coming in that format from the database. It's being processed by some code you're not showing...
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      1. USdeceze
 

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