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    <p><a href="https://stackoverflow.com/questions/6247144/how-to-load-a-folder-from-a-jar">This SO thread</a> discuss this technique in detail. Below is a useful Java method that list files from a given resource folder.</p> <pre><code>/** * List directory contents for a resource folder. Not recursive. * This is basically a brute-force implementation. * Works for regular files and also JARs. * * @author Greg Briggs * @param clazz Any java class that lives in the same place as the resources you want. * @param path Should end with "/", but not start with one. * @return Just the name of each member item, not the full paths. * @throws URISyntaxException * @throws IOException */ String[] getResourceListing(Class clazz, String path) throws URISyntaxException, IOException { URL dirURL = clazz.getClassLoader().getResource(path); if (dirURL != null &amp;&amp; dirURL.getProtocol().equals("file")) { /* A file path: easy enough */ return new File(dirURL.toURI()).list(); } if (dirURL == null) { /* * In case of a jar file, we can't actually find a directory. * Have to assume the same jar as clazz. */ String me = clazz.getName().replace(".", "/")+".class"; dirURL = clazz.getClassLoader().getResource(me); } if (dirURL.getProtocol().equals("jar")) { /* A JAR path */ String jarPath = dirURL.getPath().substring(5, dirURL.getPath().indexOf("!")); //strip out only the JAR file JarFile jar = new JarFile(URLDecoder.decode(jarPath, "UTF-8")); Enumeration&lt;JarEntry&gt; entries = jar.entries(); //gives ALL entries in jar Set&lt;String&gt; result = new HashSet&lt;String&gt;(); //avoid duplicates in case it is a subdirectory while(entries.hasMoreElements()) { String name = entries.nextElement().getName(); if (name.startsWith(path)) { //filter according to the path String entry = name.substring(path.length()); int checkSubdir = entry.indexOf("/"); if (checkSubdir &gt;= 0) { // if it is a subdirectory, we just return the directory name entry = entry.substring(0, checkSubdir); } result.add(entry); } } return result.toArray(new String[result.size()]); } throw new UnsupportedOperationException("Cannot list files for URL "+dirURL); } </code></pre>
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