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    <p><strong>Answer to #1:</strong></p> <p>You can use Javascript/AJAX to accomplish submitting the form without actually pressing submit. There are various javascript libraries that can help you accomplish this a lot easier than bare bones Javascript, namely jQuery ( <a href="http://jquery.com/" rel="nofollow">http://jquery.com/</a> ). It's not a very complicated task but you will need to learn some basic Javascript and how to use jQuery. The essential flow of things would be <em>when the form changes, submit an AJAX request to submit the form</em>. You will need a second script to take the incoming AJAX request and do the save. Try search engines for some basic jQuery tutorials, and once you have a basic grip, something like "ajax submit on form change jquery" will get you started. </p> <p><strong>Answer to #2:</strong> </p> <p>Something like this (please see my notes...)</p> <pre><code>echo '&lt;select name="rating" id="rating"&gt;'; $q = mysql_query("SELECT `option_name` FROM `options`"); while($row = mysql_fetch_assoc($q)) { echo '&lt;option value="' . $row['option_name'] . '"&gt;' . $row['option_name'] . '&lt;/option&gt;'; } echo '&lt;/select&gt;'; </code></pre> <p>If you would like the select preselected, that's pretty easy too! Taking from the last example:</p> <pre><code>$pre_selected = "Very Bad"; echo '&lt;select name="rating" id="rating"&gt;'; $q = mysql_query("SELECT `option_name` FROM `options`"); while($row = mysql_fetch_assoc($q)) { echo '&lt;option value="' . $row['option_name'] . '"'; if($row['option_name'] == $pre_selected) { echo ' selected="selected"'; } echo '&gt;' . $row['option_name'] . '&lt;/option&gt;'; } echo '&lt;/select&gt;'; </code></pre> <p>But this is the part I'd like to point a few things out:</p> <ul> <li>Don't use the old mySQL library like you are using and my examples are using. Please, use PDO, or at least mySQLi. The functions you are using are deprecated, and may not be available in PHP for much longer.</li> <li>Please, escape your data properly. Search for "SQL Injection" and you will find a massive amount of information about how your code is <em>very</em> insecure (your UPDATE, specifically) because you did not escape the values. </li> <li>Just a heads up, when/if you use jQuery, you're going to need to use <code>id="foo"</code> in addition to <code>name="foo"</code>. </li> </ul>
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    1. POHave data in mySQL database be reflective of what's displayed in a drop down menu.
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    1. USA.B. Carroll
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    1. POHave data in mySQL database be reflective of what's displayed in a drop down menu.
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    1. COThank you so much for the input. This community has awesome people. I will read this and try to apply these changes. On the SQL injections - thank you for the reminder for using deprecated functions.
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    2. COHello nezZario. The loop makes things much simpler, thank you. Can you tell me the difference between the "options" and "option_name" variable?
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    3. COThere is no `$option`s variable. ``option_name`` in the query is meant to be the column that holds your option's values. I'm not sure what you mean.
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