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POPHP AJAX Responses, how can i add different conditions?
 

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  1. POPHP AJAX Responses, how can i add different conditions?
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    <p>I want to be able to set the following:</p> <p>1) If the email already exists to return an error 2) If successful to return an error 3) if error to return error</p> <p>At the moment it works, but allows you to add same email address and sends successful response but need to add one for existing email</p> <pre><code>$('form').submit(function(){ // check if passwords match; you might want to do more thorough validation var hasError = false; var emailReg = /^([\w-\.]+@([\w-]+\.)+[\w-]{2,4})?$/; var emailaddressVal = $("#email").val(); if(emailaddressVal == '') { $("#email").after('&lt;span class="error"&gt;Please enter your email address.&lt;/span&gt;'); hasError = true; } else if(!emailReg.test(emailaddressVal)) { $("#email").after('&lt;span class="error"&gt;Enter a valid email address.&lt;/span&gt;'); hasError = true; } else if(hasError == false) { // make ajax post request and store the response in "response" variable $.post('submit.php', $(this).serialize(), function(response){ // process response here (assume JSON object has boolean property "ok" if(response.ok==true){ // sweet, it worked! alert('OK!'); }else{ // handle error alert('Ooops'); } }, 'json'); } // stop the form from being submitted return false; }); </code></pre> <p>And the php is:</p> <pre><code>&lt;?php ini_set('display_errors', 1); error_reporting(E_ALL); $con = mysql_connect("localhost","root",""); //Replace with your actual MySQL DB Username and Password if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("table", $con); //Replace with your MySQL DB Name $first_name=mysql_real_escape_string($_POST['firstname']); $last_name=mysql_real_escape_string($_POST['lastname']); $email=mysql_real_escape_string($_POST['email']); $sql="INSERT INTO email_list (first_name,last_name,email) VALUES ('$first_name','$last_name','$email')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "The form data was successfully added to your database."; mysql_close($con); ?&gt; </code></pre> <p>Thanks!</p>
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    1. USViral Shah
    1. USJames Brandon
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    1. COhttp://docs.jquery.com/Plugins/Validation/validate refer this link you can do it easily.
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      1. USDipesh Parmar
    2. COplease.. dont use `mysql_*`! it's **deprecated**. Use **`PDO`**! (or `mysqli_*`)
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      1. USStasGrin
    3. COand.. real escaping? [nice way to got all data lost](http://stackoverflow.com/questions/5741187/sql-injection-that-gets-around-mysql-real-escape-string)
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