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  1. PO
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    <p>You tagged <code>preg-match</code>, so we'll assume PHP and PCRE. This is fairly easy using <code>([\d,]+)</code> capture groups:</p> <pre><code>/([\d,]+)\s+people\s+.*24 hours,\s+([\d,]+)\s+people.*/sm </code></pre> <ul> <li><code>^</code> = start of the string (removed after comments)</li> <li><code>([\d,]+)</code> the string of digits and commas that make up the first number, captured in <code>()</code></li> <li><code>.+?</code> Non-greed set of any characters following the number up until...</li> <li><code>hours,</code> : ...the literal string hours followed by a comma</li> <li><code>([\d,]+)</code> = Another <code>()</code> capture group for the second number</li> <li><code>.*</code> = Everything else up to the end of the string.</li> <li><code>/sm</code> The multi-line modifier and <code>s</code> "dotall" which makes the <code>.</code> match newlines</li> </ul> <p>Note that this <em>doesn't</em> validate that the number is actually a real number, with the <code>,</code> thousands separator in the right place. It just looks for a string of digits and commas. So even something invalid like <code>99,,112345,</code> would match in that position. But if you don't expect your input to look like that, and <em>do</em> expect a <em>real</em> number to appear at the start of the string and after <code>hours,</code> this isn't a big deal.</p> <p>To match a <em>valid</em> number you would need something more complex like</p> <pre><code>((?:\d{1,3},)(?:\d{3},)*(?:\d{1,3})) </code></pre> <p>And that still isn't even totally right, as it would match 123,456,1.</p> <h3>Quick test in PHP:</h3> <pre><code>$pattern = '/([\d,]+)\s+people\s+.*24 hours,\s+([\d,]+)\s+people.*/sm'; preg_match($pattern, $string, $matches); print_r($matches); Array ( [0] =&gt; 8,222,865 people have bought the game. &lt;/p&gt; &lt;p&gt; In the last 24 hours, 7,087 people bought the game. &lt;/p&gt; [1] =&gt; 8,222,865 [2] =&gt; 7,087 ) </code></pre>
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    1. PONeed to match 2 numbers from source
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    1. USMichael Berkowski
    1. USMichael Berkowski
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    1. PONeed to match 2 numbers from source
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    1. CO@Sedoc94 Then take off the anchor `^` which forces the number to occur at the beginning of the string.
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      1. USMichael Berkowski
    2. COHi, I made a mistake. Can you please use the new html code to use this regex on? I really appreciate your thoroughly explained answer!
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      1. USKid Diamond
    3. COGetting it straightened out...
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      1. USMichael Berkowski
 

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