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    <p>How to get the webservice client address for a jax-ws service depends on whether you are:</p> <ul> <li>Running your webservice as a servlet (in a Java EE container), or</li> <li>Running your webservice as a stand-alone application (Java SE 6 or 7).</li> </ul> <p><strong>Servlet Webservices</strong> If your webservice is a servlet then use the solution of the first post that contains the following:</p> <pre><code>HttpServletRequest req = (HttpServletRequest)mc.get(MessageContext.SERVLET_REQUEST); </code></pre> <p><strong>Application Webservices : JAX-WS 2.1</strong> If you are using a Java application (Java SE) you have no servlet context, so the <code>HttpServletRequest</code> will be null. You need to use the method of the later post, the one that has the following line:</p> <pre><code>HttpExchange exchange = (HttpExchange)msgx.get(JAXWSProperties.HTTP_EXCHANGE); </code></pre> <p>Note: this only works with the JAX-WS 2.1 stack/reference implementation.</p> <p><strong>Application Webservices : JAX-WS 2.2</strong></p> <p>In JAX-WS 2.2 the value of <code>JAXWSProperties.HTTP_EXCHANGE</code> has changed from "com.sun.xml.ws.http.exchange" (the value it was in JAX-WS 2.1) to "com.sun.xml.internal.ws.http.exchange". That means that a call to </p> <pre><code>HttpExchange exchange = (HttpExchange)msgx.get(JAXWSProperties.HTTP_EXCHANGE); InetSocketAddress remoteAddress = exchange.getRemoteAddress(); String remoteHost = remoteAddress.getHostName(); </code></pre> <p>will return null in JAX-WS 2.2 and you'll get a <code>NullPointerException</code> on the second line, and more importantly, cannot get the remote address of the client.</p> <p>If you use the following call instead (using the literal value, ugh!):</p> <pre><code>HttpExchange exchange = (HttpExchange)msgx.get("com.sun.xml.ws.http.exchange"); InetSocketAddress remoteAddress = exchange.getRemoteAddress(); String remoteHost = remoteAddress.getHostName(); </code></pre> <p>you will get a non-null value and will be able to obtain the client address.</p> <p>So, how you get the remote address of the client depends on how you deploy your code (servlet or application) and which version of JAX-WS you are using (JAX-WS 2.1 or 2.2).</p> <p><strong>Recommendations</strong></p> <ul> <li><p><strong>Servlets</strong>: If you are deploying your JAX-WS webservice in a servlet you can always use the call to get the property <code>MessageContext.SERVLET_REQUEST</code> no matter what version of JAX-WS 2 you are using.</p></li> <li><p><strong>Applications</strong>: If you are deploying your JAX-WS webservice in an application you can always use the call <code>HttpExchange exchange = (HttpExchange)msgx.get("com.sun.xml.ws.http.exchange");</code> no matter whether you are using JAX-WS 2.1 or 2.2, therefore it is probably better to use the string literal in your code rather than the symbolic <code>JAXWSProperties.HTTP_EXCHANGE</code>. </p></li> </ul> <p>As distasteful as using the literal is, it is better to have more robust code that works across JAX-WS versions rather than prettier code that doesn't.</p> <p>I hope the JAX-WS team correct the issue sometime and restore the value of <code>JAXWSProperties.HTTP_EXCHANGE</code> to the useful value again.</p> <p>Many thanks to the earlier posters that showed the various ways of finding the remote address of JAX-WS clients. The information was very useful :)</p>
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