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POJackson deserialize generic with unknown property name
 

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    <p>I have following <code>JSON</code>. And I am parsing it using <code> Jackson</code> Parser</p> <pre><code> { "code": 0, "response": { "pagination": { "page": 1, "limit": 20, "count": 5, "pageCount": 1 }, "random": [ .... ] } } </code></pre> <p>Now I have simple <code> POJO </code> classes created for various <code>random</code> object. I expect 3-4 different types of <code> random </code> object. So instead of creating different wrapper classes for different types of 'random' object I created a generic one</p> <p><b>EDITED CLASS:</b></p> <pre><code>public class PaginatedResponse&lt;E&gt; { private Pagination pagination; private List&lt;E&gt; responseList; public Pagination getPagination() { return pagination; } public void setPagination(Pagination pagination) { this.pagination = pagination; } public List&lt;E&gt; getResponseList() { return responseList; } public void setResponseList(List&lt;E&gt; responseList) { this.responseList = responseList; } } </code></pre> <p>Now For mapping it I used,</p> <pre><code> JsonNode tree = mapper.readTree(response); TypeReference&lt;PaginatedResponse&lt;LocationParent&gt;&gt; ref = new TypeReference&lt;PaginatedResponse&lt;LocationParent&gt;&gt;() { }; PaginatedResponse&lt;LocationParent&gt; resp = mapper.convertValue(tree.get("response"), ref); </code></pre> <p>But i am not able to map <code>responseList</code>. I get the <code> pagination </code> object but the <code>responseList</code> is always null. Now how to dynamically provide <code>property name</code> for <code>responseList</code>.</p> <p>Please help </p>
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    1. USvKashyap
    1. USvKashyap
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    1. COGeneric wrapper works fine, as long as you pass non-generic type when deserializing (otherwise Jackson does not know type of 'random' beyond it being java.lang.Object). This can be done by passing `TypeReference`, or if it's fully dynamic, using `TypeFactory.constructGenericType()` (or whatever the exact name is). But you should not require custom deserializer as long as there is a POJO for 'random'.
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      1. USStaxMan
    2. COThanks a lot for helping in all my previous questions also. I followed your advice and used `TypeReference`. Have updated my question.
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      1. USvKashyap
    3. COSo far so good! What is the missing part here?
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      1. USStaxMan
 

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